Metamath Proof Explorer


Theorem z12bday

Description: A dyadic fraction has a finite birthday. (Contributed by Scott Fenton, 20-Aug-2025) (Proof shortened by Scott Fenton, 22-Feb-2026)

Ref Expression
Assertion z12bday ( 𝐴 ∈ ℤs[1/2] → ( bday ‘ 𝐴 ) ∈ ω )

Proof

Step Hyp Ref Expression
1 z12bdaylem ⊢ ( ( 𝐴 ∈ ℤs[1/2] ∧ 0s ≤s 𝐴 ) → ( bday ‘ 𝐴 ) ∈ ω )
2 0no ⊢ 0s ∈ No
3 z12no ⊢ ( 𝐴 ∈ ℤs[1/2] → 𝐴 ∈ No )
4 lestric ⊢ ( ( 0s ∈ No ∧ 𝐴 ∈ No ) → ( 0s ≤s 𝐴 ∨ 𝐴 ≤s 0s ) )
5 2 3 4 sylancr ⊢ ( 𝐴 ∈ ℤs[1/2] → ( 0s ≤s 𝐴 ∨ 𝐴 ≤s 0s ) )
6 5 ord ⊢ ( 𝐴 ∈ ℤs[1/2] → ( ¬ 0s ≤s 𝐴 → 𝐴 ≤s 0s ) )
7 lenegs ⊢ ( ( 𝐴 ∈ No ∧ 0s ∈ No ) → ( 𝐴 ≤s 0s ↔ ( -us ‘ 0s ) ≤s ( -us ‘ 𝐴 ) ) )
8 3 2 7 sylancl ⊢ ( 𝐴 ∈ ℤs[1/2] → ( 𝐴 ≤s 0s ↔ ( -us ‘ 0s ) ≤s ( -us ‘ 𝐴 ) ) )
9 neg0s ⊢ ( -us ‘ 0s ) = 0s
10 9 breq1i ⊢ ( ( -us ‘ 0s ) ≤s ( -us ‘ 𝐴 ) ↔ 0s ≤s ( -us ‘ 𝐴 ) )
11 8 10 bitrdi ⊢ ( 𝐴 ∈ ℤs[1/2] → ( 𝐴 ≤s 0s ↔ 0s ≤s ( -us ‘ 𝐴 ) ) )
12 z12negscl ⊢ ( 𝐴 ∈ ℤs[1/2] → ( -us ‘ 𝐴 ) ∈ ℤs[1/2] )
13 z12bdaylem ⊢ ( ( ( -us ‘ 𝐴 ) ∈ ℤs[1/2] ∧ 0s ≤s ( -us ‘ 𝐴 ) ) → ( bday ‘ ( -us ‘ 𝐴 ) ) ∈ ω )
14 13 ex ⊢ ( ( -us ‘ 𝐴 ) ∈ ℤs[1/2] → ( 0s ≤s ( -us ‘ 𝐴 ) → ( bday ‘ ( -us ‘ 𝐴 ) ) ∈ ω ) )
15 12 14 syl ⊢ ( 𝐴 ∈ ℤs[1/2] → ( 0s ≤s ( -us ‘ 𝐴 ) → ( bday ‘ ( -us ‘ 𝐴 ) ) ∈ ω ) )
16 negbday ⊢ ( 𝐴 ∈ No → ( bday ‘ ( -us ‘ 𝐴 ) ) = ( bday ‘ 𝐴 ) )
17 3 16 syl ⊢ ( 𝐴 ∈ ℤs[1/2] → ( bday ‘ ( -us ‘ 𝐴 ) ) = ( bday ‘ 𝐴 ) )
18 17 eleq1d ⊢ ( 𝐴 ∈ ℤs[1/2] → ( ( bday ‘ ( -us ‘ 𝐴 ) ) ∈ ω ↔ ( bday ‘ 𝐴 ) ∈ ω ) )
19 15 18 sylibd ⊢ ( 𝐴 ∈ ℤs[1/2] → ( 0s ≤s ( -us ‘ 𝐴 ) → ( bday ‘ 𝐴 ) ∈ ω ) )
20 11 19 sylbid ⊢ ( 𝐴 ∈ ℤs[1/2] → ( 𝐴 ≤s 0s → ( bday ‘ 𝐴 ) ∈ ω ) )
21 6 20 syld ⊢ ( 𝐴 ∈ ℤs[1/2] → ( ¬ 0s ≤s 𝐴 → ( bday ‘ 𝐴 ) ∈ ω ) )
22 21 imp ⊢ ( ( 𝐴 ∈ ℤs[1/2] ∧ ¬ 0s ≤s 𝐴 ) → ( bday ‘ 𝐴 ) ∈ ω )
23 1 22 pm2.61dan ⊢ ( 𝐴 ∈ ℤs[1/2] → ( bday ‘ 𝐴 ) ∈ ω )