Metamath Proof Explorer


Theorem abvfval

Description: Value of the set of absolute values. (Contributed by Mario Carneiro, 8-Sep-2014)

Ref Expression
Hypotheses abvfval.a ⊢ A = AbsVal ⁡ R
abvfval.b ⊢ B = Base R
abvfval.p ⊢ + ˙ = + R
abvfval.t ⊢ · ˙ = ⋅ R
abvfval.z ⊢ 0 ˙ = 0 R
Assertion abvfval ⊢ R ∈ Ring → A = f ∈ 0 +∞ B | ∀ x ∈ B f ⁡ x = 0 ↔ x = 0 ˙ ∧ ∀ y ∈ B f ⁡ x · ˙ y = f ⁡ x ⁢ f ⁡ y ∧ f ⁡ x + ˙ y ≤ f ⁡ x + f ⁡ y

Proof

Step Hyp Ref Expression
1 abvfval.a ⊢ A = AbsVal ⁡ R
2 abvfval.b ⊢ B = Base R
3 abvfval.p ⊢ + ˙ = + R
4 abvfval.t ⊢ · ˙ = ⋅ R
5 abvfval.z ⊢ 0 ˙ = 0 R
6 fveq2 ⊢ r = R → Base r = Base R
7 6 2 eqtr4di ⊢ r = R → Base r = B
8 7 oveq2d ⊢ r = R → 0 +∞ Base r = 0 +∞ B
9 fveq2 ⊢ r = R → 0 r = 0 R
10 9 5 eqtr4di ⊢ r = R → 0 r = 0 ˙
11 10 eqeq2d ⊢ r = R → x = 0 r ↔ x = 0 ˙
12 11 bibi2d ⊢ r = R → f ⁡ x = 0 ↔ x = 0 r ↔ f ⁡ x = 0 ↔ x = 0 ˙
13 fveq2 ⊢ r = R → ⋅ r = ⋅ R
14 13 4 eqtr4di ⊢ r = R → ⋅ r = · ˙
15 14 oveqd ⊢ r = R → x ⋅ r y = x · ˙ y
16 15 fveqeq2d ⊢ r = R → f ⁡ x ⋅ r y = f ⁡ x ⁢ f ⁡ y ↔ f ⁡ x · ˙ y = f ⁡ x ⁢ f ⁡ y
17 fveq2 ⊢ r = R → + r = + R
18 17 3 eqtr4di ⊢ r = R → + r = + ˙
19 18 oveqd ⊢ r = R → x + r y = x + ˙ y
20 19 fveq2d ⊢ r = R → f ⁡ x + r y = f ⁡ x + ˙ y
21 20 breq1d ⊢ r = R → f ⁡ x + r y ≤ f ⁡ x + f ⁡ y ↔ f ⁡ x + ˙ y ≤ f ⁡ x + f ⁡ y
22 16 21 anbi12d ⊢ r = R → f ⁡ x ⋅ r y = f ⁡ x ⁢ f ⁡ y ∧ f ⁡ x + r y ≤ f ⁡ x + f ⁡ y ↔ f ⁡ x · ˙ y = f ⁡ x ⁢ f ⁡ y ∧ f ⁡ x + ˙ y ≤ f ⁡ x + f ⁡ y
23 7 22 raleqbidv ⊢ r = R → ∀ y ∈ Base r f ⁡ x ⋅ r y = f ⁡ x ⁢ f ⁡ y ∧ f ⁡ x + r y ≤ f ⁡ x + f ⁡ y ↔ ∀ y ∈ B f ⁡ x · ˙ y = f ⁡ x ⁢ f ⁡ y ∧ f ⁡ x + ˙ y ≤ f ⁡ x + f ⁡ y
24 12 23 anbi12d ⊢ r = R → f ⁡ x = 0 ↔ x = 0 r ∧ ∀ y ∈ Base r f ⁡ x ⋅ r y = f ⁡ x ⁢ f ⁡ y ∧ f ⁡ x + r y ≤ f ⁡ x + f ⁡ y ↔ f ⁡ x = 0 ↔ x = 0 ˙ ∧ ∀ y ∈ B f ⁡ x · ˙ y = f ⁡ x ⁢ f ⁡ y ∧ f ⁡ x + ˙ y ≤ f ⁡ x + f ⁡ y
25 7 24 raleqbidv ⊢ r = R → ∀ x ∈ Base r f ⁡ x = 0 ↔ x = 0 r ∧ ∀ y ∈ Base r f ⁡ x ⋅ r y = f ⁡ x ⁢ f ⁡ y ∧ f ⁡ x + r y ≤ f ⁡ x + f ⁡ y ↔ ∀ x ∈ B f ⁡ x = 0 ↔ x = 0 ˙ ∧ ∀ y ∈ B f ⁡ x · ˙ y = f ⁡ x ⁢ f ⁡ y ∧ f ⁡ x + ˙ y ≤ f ⁡ x + f ⁡ y
26 8 25 rabeqbidv ⊢ r = R → f ∈ 0 +∞ Base r | ∀ x ∈ Base r f ⁡ x = 0 ↔ x = 0 r ∧ ∀ y ∈ Base r f ⁡ x ⋅ r y = f ⁡ x ⁢ f ⁡ y ∧ f ⁡ x + r y ≤ f ⁡ x + f ⁡ y = f ∈ 0 +∞ B | ∀ x ∈ B f ⁡ x = 0 ↔ x = 0 ˙ ∧ ∀ y ∈ B f ⁡ x · ˙ y = f ⁡ x ⁢ f ⁡ y ∧ f ⁡ x + ˙ y ≤ f ⁡ x + f ⁡ y
27 df-abv ⊢ AbsVal = r ∈ Ring ⟼ f ∈ 0 +∞ Base r | ∀ x ∈ Base r f ⁡ x = 0 ↔ x = 0 r ∧ ∀ y ∈ Base r f ⁡ x ⋅ r y = f ⁡ x ⁢ f ⁡ y ∧ f ⁡ x + r y ≤ f ⁡ x + f ⁡ y
28 ovex ⊢ 0 +∞ B ∈ V
29 28 rabex ⊢ f ∈ 0 +∞ B | ∀ x ∈ B f ⁡ x = 0 ↔ x = 0 ˙ ∧ ∀ y ∈ B f ⁡ x · ˙ y = f ⁡ x ⁢ f ⁡ y ∧ f ⁡ x + ˙ y ≤ f ⁡ x + f ⁡ y ∈ V
30 26 27 29 fvmpt ⊢ R ∈ Ring → AbsVal ⁡ R = f ∈ 0 +∞ B | ∀ x ∈ B f ⁡ x = 0 ↔ x = 0 ˙ ∧ ∀ y ∈ B f ⁡ x · ˙ y = f ⁡ x ⁢ f ⁡ y ∧ f ⁡ x + ˙ y ≤ f ⁡ x + f ⁡ y
31 1 30 eqtrid ⊢ R ∈ Ring → A = f ∈ 0 +∞ B | ∀ x ∈ B f ⁡ x = 0 ↔ x = 0 ˙ ∧ ∀ y ∈ B f ⁡ x · ˙ y = f ⁡ x ⁢ f ⁡ y ∧ f ⁡ x + ˙ y ≤ f ⁡ x + f ⁡ y