Metamath Proof Explorer


Theorem bj-restb

Description: An elementwise intersection by a set on a family containing a superset of that set contains that set. (Contributed by BJ, 27-Apr-2021)

Ref Expression
Assertion bj-restb ⊢ X ∈ V → A ⊆ B ∧ B ∈ X → A ∈ X ↾ 𝑡 A

Proof

Step Hyp Ref Expression
1 id ⊢ A ⊆ B → A ⊆ B
2 ssidd ⊢ A ⊆ B → A ⊆ A
3 1 2 ssind ⊢ A ⊆ B → A ⊆ B ∩ A
4 inss2 ⊢ B ∩ A ⊆ A
5 4 a1i ⊢ A ⊆ B → B ∩ A ⊆ A
6 3 5 eqssd ⊢ A ⊆ B → A = B ∩ A
7 eleq1 ⊢ y = B → y ∈ X ↔ B ∈ X
8 ineq1 ⊢ y = B → y ∩ A = B ∩ A
9 8 eqeq2d ⊢ y = B → A = y ∩ A ↔ A = B ∩ A
10 7 9 anbi12d ⊢ y = B → y ∈ X ∧ A = y ∩ A ↔ B ∈ X ∧ A = B ∩ A
11 10 spcegv ⊢ B ∈ X → B ∈ X ∧ A = B ∩ A → ∃ y y ∈ X ∧ A = y ∩ A
12 11 expd ⊢ B ∈ X → B ∈ X → A = B ∩ A → ∃ y y ∈ X ∧ A = y ∩ A
13 12 pm2.43i ⊢ B ∈ X → A = B ∩ A → ∃ y y ∈ X ∧ A = y ∩ A
14 6 13 mpan9 ⊢ A ⊆ B ∧ B ∈ X → ∃ y y ∈ X ∧ A = y ∩ A
15 df-rex ⊢ ∃ y ∈ X A = y ∩ A ↔ ∃ y y ∈ X ∧ A = y ∩ A
16 14 15 sylibr ⊢ A ⊆ B ∧ B ∈ X → ∃ y ∈ X A = y ∩ A
17 16 adantl ⊢ X ∈ V ∧ A ⊆ B ∧ B ∈ X → ∃ y ∈ X A = y ∩ A
18 ssexg ⊢ A ⊆ B ∧ B ∈ X → A ∈ V
19 elrest ⊢ X ∈ V ∧ A ∈ V → A ∈ X ↾ 𝑡 A ↔ ∃ y ∈ X A = y ∩ A
20 18 19 sylan2 ⊢ X ∈ V ∧ A ⊆ B ∧ B ∈ X → A ∈ X ↾ 𝑡 A ↔ ∃ y ∈ X A = y ∩ A
21 17 20 mpbird ⊢ X ∈ V ∧ A ⊆ B ∧ B ∈ X → A ∈ X ↾ 𝑡 A
22 21 ex ⊢ X ∈ V → A ⊆ B ∧ B ∈ X → A ∈ X ↾ 𝑡 A