Metamath Proof Explorer


Theorem bnj1529

Description: Technical lemma for bnj1522 . This lemma may no longer be used or have become an indirect lemma of the theorem in question (i.e. a lemma of a lemma... of the theorem). (Contributed by Jonathan Ben-Naim, 3-Jun-2011) (New usage is discouraged.)

Ref Expression
Hypotheses bnj1529.1 ⊢ χ → ∀ x ∈ A F ⁡ x = G ⁡ x F ↾ pred x A R
bnj1529.2 ⊢ w ∈ F → ∀ x w ∈ F
Assertion bnj1529 ⊢ χ → ∀ y ∈ A F ⁡ y = G ⁡ y F ↾ pred y A R

Proof

Step Hyp Ref Expression
1 bnj1529.1 ⊢ χ → ∀ x ∈ A F ⁡ x = G ⁡ x F ↾ pred x A R
2 bnj1529.2 ⊢ w ∈ F → ∀ x w ∈ F
3 nfv ⊢ Ⅎ y F ⁡ x = G ⁡ x F ↾ pred x A R
4 2 nfcii ⊢ Ⅎ _ x F
5 nfcv ⊢ Ⅎ _ x y
6 4 5 nffv ⊢ Ⅎ _ x F ⁡ y
7 nfcv ⊢ Ⅎ _ x G
8 nfcv ⊢ Ⅎ _ x pred y A R
9 4 8 nfres ⊢ Ⅎ _ x F ↾ pred y A R
10 5 9 nfop ⊢ Ⅎ _ x y F ↾ pred y A R
11 7 10 nffv ⊢ Ⅎ _ x G ⁡ y F ↾ pred y A R
12 6 11 nfeq ⊢ Ⅎ x F ⁡ y = G ⁡ y F ↾ pred y A R
13 fveq2 ⊢ x = y → F ⁡ x = F ⁡ y
14 id ⊢ x = y → x = y
15 bnj602 ⊢ x = y → pred x A R = pred y A R
16 15 reseq2d ⊢ x = y → F ↾ pred x A R = F ↾ pred y A R
17 14 16 opeq12d ⊢ x = y → x F ↾ pred x A R = y F ↾ pred y A R
18 17 fveq2d ⊢ x = y → G ⁡ x F ↾ pred x A R = G ⁡ y F ↾ pred y A R
19 13 18 eqeq12d ⊢ x = y → F ⁡ x = G ⁡ x F ↾ pred x A R ↔ F ⁡ y = G ⁡ y F ↾ pred y A R
20 3 12 19 cbvralw ⊢ ∀ x ∈ A F ⁡ x = G ⁡ x F ↾ pred x A R ↔ ∀ y ∈ A F ⁡ y = G ⁡ y F ↾ pred y A R
21 1 20 sylib ⊢ χ → ∀ y ∈ A F ⁡ y = G ⁡ y F ↾ pred y A R