Metamath Proof Explorer


Theorem cdlemk49

Description: Part of proof of Lemma K of Crawley p. 118. Line 5, p. 120. G , I stand for g, h. X represents tau. (Contributed by NM, 23-Jul-2013)

Ref Expression
Hypotheses cdlemk5.b ⊢ B = Base K
cdlemk5.l ⊢ ≤ ˙ = ≤ K
cdlemk5.j ⊢ ∨ ˙ = join ⁡ K
cdlemk5.m ⊢ ∧ ˙ = meet ⁡ K
cdlemk5.a ⊢ A = Atoms ⁡ K
cdlemk5.h ⊢ H = LHyp ⁡ K
cdlemk5.t ⊢ T = LTrn ⁡ K ⁡ W
cdlemk5.r ⊢ R = trL ⁡ K ⁡ W
cdlemk5.z ⊢ Z = P ∨ ˙ R ⁡ b ∧ ˙ N ⁡ P ∨ ˙ R ⁡ b ∘ F -1
cdlemk5.y ⊢ Y = P ∨ ˙ R ⁡ g ∧ ˙ Z ∨ ˙ R ⁡ g ∘ b -1
cdlemk5.x ⊢ X = ι z ∈ T | ∀ b ∈ T b ≠ I ↾ B ∧ R ⁡ b ≠ R ⁡ F ∧ R ⁡ b ≠ R ⁡ g → z ⁡ P = Y
Assertion cdlemk49 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ G ∈ T ∧ G ≠ I ↾ B ∧ N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N ∧ I ∈ T ∧ I ≠ I ↾ B → ⦋ G / g⦌ X ∘ ⦋ I / g⦌ X ⁡ P ≤ ˙ ⦋ G / g⦌ X ⁡ P ∨ ˙ R ⁡ ⦋ I / g⦌ X

Proof

Step Hyp Ref Expression
1 cdlemk5.b ⊢ B = Base K
2 cdlemk5.l ⊢ ≤ ˙ = ≤ K
3 cdlemk5.j ⊢ ∨ ˙ = join ⁡ K
4 cdlemk5.m ⊢ ∧ ˙ = meet ⁡ K
5 cdlemk5.a ⊢ A = Atoms ⁡ K
6 cdlemk5.h ⊢ H = LHyp ⁡ K
7 cdlemk5.t ⊢ T = LTrn ⁡ K ⁡ W
8 cdlemk5.r ⊢ R = trL ⁡ K ⁡ W
9 cdlemk5.z ⊢ Z = P ∨ ˙ R ⁡ b ∧ ˙ N ⁡ P ∨ ˙ R ⁡ b ∘ F -1
10 cdlemk5.y ⊢ Y = P ∨ ˙ R ⁡ g ∧ ˙ Z ∨ ˙ R ⁡ g ∘ b -1
11 cdlemk5.x ⊢ X = ι z ∈ T | ∀ b ∈ T b ≠ I ↾ B ∧ R ⁡ b ≠ R ⁡ F ∧ R ⁡ b ≠ R ⁡ g → z ⁡ P = Y
12 simp11 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ G ∈ T ∧ G ≠ I ↾ B ∧ N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N ∧ I ∈ T ∧ I ≠ I ↾ B → K ∈ HL ∧ W ∈ H
13 simp12 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ G ∈ T ∧ G ≠ I ↾ B ∧ N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N ∧ I ∈ T ∧ I ≠ I ↾ B → F ∈ T ∧ F ≠ I ↾ B
14 simp13 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ G ∈ T ∧ G ≠ I ↾ B ∧ N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N ∧ I ∈ T ∧ I ≠ I ↾ B → G ∈ T ∧ G ≠ I ↾ B
15 simp21 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ G ∈ T ∧ G ≠ I ↾ B ∧ N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N ∧ I ∈ T ∧ I ≠ I ↾ B → N ∈ T
16 simp22 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ G ∈ T ∧ G ≠ I ↾ B ∧ N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N ∧ I ∈ T ∧ I ≠ I ↾ B → P ∈ A ∧ ¬ P ≤ ˙ W
17 simp23 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ G ∈ T ∧ G ≠ I ↾ B ∧ N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N ∧ I ∈ T ∧ I ≠ I ↾ B → R ⁡ F = R ⁡ N
18 1 2 3 4 5 6 7 8 9 10 11 cdlemk35s ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ G ∈ T ∧ G ≠ I ↾ B ∧ N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N → ⦋ G / g⦌ X ∈ T
19 12 13 14 15 16 17 18 syl132anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ G ∈ T ∧ G ≠ I ↾ B ∧ N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N ∧ I ∈ T ∧ I ≠ I ↾ B → ⦋ G / g⦌ X ∈ T
20 simp3 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ G ∈ T ∧ G ≠ I ↾ B ∧ N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N ∧ I ∈ T ∧ I ≠ I ↾ B → I ∈ T ∧ I ≠ I ↾ B
21 1 2 3 4 5 6 7 8 9 10 11 cdlemk35s ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ I ∈ T ∧ I ≠ I ↾ B ∧ N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N → ⦋ I / g⦌ X ∈ T
22 12 13 20 15 16 17 21 syl132anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ G ∈ T ∧ G ≠ I ↾ B ∧ N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N ∧ I ∈ T ∧ I ≠ I ↾ B → ⦋ I / g⦌ X ∈ T
23 6 7 ltrncom ⊢ K ∈ HL ∧ W ∈ H ∧ ⦋ G / g⦌ X ∈ T ∧ ⦋ I / g⦌ X ∈ T → ⦋ G / g⦌ X ∘ ⦋ I / g⦌ X = ⦋ I / g⦌ X ∘ ⦋ G / g⦌ X
24 12 19 22 23 syl3anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ G ∈ T ∧ G ≠ I ↾ B ∧ N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N ∧ I ∈ T ∧ I ≠ I ↾ B → ⦋ G / g⦌ X ∘ ⦋ I / g⦌ X = ⦋ I / g⦌ X ∘ ⦋ G / g⦌ X
25 24 fveq1d ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ G ∈ T ∧ G ≠ I ↾ B ∧ N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N ∧ I ∈ T ∧ I ≠ I ↾ B → ⦋ G / g⦌ X ∘ ⦋ I / g⦌ X ⁡ P = ⦋ I / g⦌ X ∘ ⦋ G / g⦌ X ⁡ P
26 simp2 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ G ∈ T ∧ G ≠ I ↾ B ∧ N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N ∧ I ∈ T ∧ I ≠ I ↾ B → N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N
27 1 2 3 4 5 6 7 8 9 10 11 cdlemk48 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ I ∈ T ∧ I ≠ I ↾ B ∧ N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ G ≠ I ↾ B → ⦋ I / g⦌ X ∘ ⦋ G / g⦌ X ⁡ P ≤ ˙ ⦋ G / g⦌ X ⁡ P ∨ ˙ R ⁡ ⦋ I / g⦌ X
28 12 13 20 26 14 27 syl311anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ G ∈ T ∧ G ≠ I ↾ B ∧ N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N ∧ I ∈ T ∧ I ≠ I ↾ B → ⦋ I / g⦌ X ∘ ⦋ G / g⦌ X ⁡ P ≤ ˙ ⦋ G / g⦌ X ⁡ P ∨ ˙ R ⁡ ⦋ I / g⦌ X
29 25 28 eqbrtrd ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ G ∈ T ∧ G ≠ I ↾ B ∧ N ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ R ⁡ F = R ⁡ N ∧ I ∈ T ∧ I ≠ I ↾ B → ⦋ G / g⦌ X ∘ ⦋ I / g⦌ X ⁡ P ≤ ˙ ⦋ G / g⦌ X ⁡ P ∨ ˙ R ⁡ ⦋ I / g⦌ X