Metamath Proof Explorer


Theorem chssoc

Description: A closed subspace less than its orthocomplement is zero. (Contributed by NM, 14-Jun-2006) (New usage is discouraged.)

Ref Expression
Assertion chssoc ⊢ A ∈ C ℋ → A ⊆ ⊥ ⁡ A ↔ A = 0 ℋ

Proof

Step Hyp Ref Expression
1 inidm ⊢ A ∩ A = A
2 sslin ⊢ A ⊆ ⊥ ⁡ A → A ∩ A ⊆ A ∩ ⊥ ⁡ A
3 1 2 eqsstrrid ⊢ A ⊆ ⊥ ⁡ A → A ⊆ A ∩ ⊥ ⁡ A
4 chocin ⊢ A ∈ C ℋ → A ∩ ⊥ ⁡ A = 0 ℋ
5 4 sseq2d ⊢ A ∈ C ℋ → A ⊆ A ∩ ⊥ ⁡ A ↔ A ⊆ 0 ℋ
6 chle0 ⊢ A ∈ C ℋ → A ⊆ 0 ℋ ↔ A = 0 ℋ
7 5 6 bitrd ⊢ A ∈ C ℋ → A ⊆ A ∩ ⊥ ⁡ A ↔ A = 0 ℋ
8 3 7 imbitrid ⊢ A ∈ C ℋ → A ⊆ ⊥ ⁡ A → A = 0 ℋ
9 simpr ⊢ A ∈ C ℋ ∧ A = 0 ℋ → A = 0 ℋ
10 choccl ⊢ A ∈ C ℋ → ⊥ ⁡ A ∈ C ℋ
11 ch0le ⊢ ⊥ ⁡ A ∈ C ℋ → 0 ℋ ⊆ ⊥ ⁡ A
12 10 11 syl ⊢ A ∈ C ℋ → 0 ℋ ⊆ ⊥ ⁡ A
13 12 adantr ⊢ A ∈ C ℋ ∧ A = 0 ℋ → 0 ℋ ⊆ ⊥ ⁡ A
14 9 13 eqsstrd ⊢ A ∈ C ℋ ∧ A = 0 ℋ → A ⊆ ⊥ ⁡ A
15 14 ex ⊢ A ∈ C ℋ → A = 0 ℋ → A ⊆ ⊥ ⁡ A
16 8 15 impbid ⊢ A ∈ C ℋ → A ⊆ ⊥ ⁡ A ↔ A = 0 ℋ