Metamath Proof Explorer


Theorem cpmatel2

Description: Another property of a constant polynomial matrix. (Contributed by AV, 16-Nov-2019) (Proof shortened by AV, 27-Nov-2019)

Ref Expression
Hypotheses cpmat.s S=NConstPolyMatR
cpmat.p P=Poly1R
cpmat.c C=NMatP
cpmat.b B=BaseC
cpmatel2.k K=BaseR
cpmatel2.a A=algScP
Assertion cpmatel2 NFinRRingMBMSiNjNkKiMj=Ak

Proof

Step Hyp Ref Expression
1 cpmat.s S=NConstPolyMatR
2 cpmat.p P=Poly1R
3 cpmat.c C=NMatP
4 cpmat.b B=BaseC
5 cpmatel2.k K=BaseR
6 cpmatel2.a A=algScP
7 1 2 3 4 cpmatel NFinRRingMBMSiNjNlcoe1iMjl=0R
8 simpl2 NFinRRingMBiNjNRRing
9 eqid BaseP=BaseP
10 simprl NFinRRingMBiNjNiN
11 simprr NFinRRingMBiNjNjN
12 simpl3 NFinRRingMBiNjNMB
13 3 9 4 10 11 12 matecld NFinRRingMBiNjNiMjBaseP
14 eqid 0R=0R
15 5 14 2 9 6 cply1coe0bi RRingiMjBasePkKiMj=Aklcoe1iMjl=0R
16 8 13 15 syl2anc NFinRRingMBiNjNkKiMj=Aklcoe1iMjl=0R
17 16 bicomd NFinRRingMBiNjNlcoe1iMjl=0RkKiMj=Ak
18 17 2ralbidva NFinRRingMBiNjNlcoe1iMjl=0RiNjNkKiMj=Ak
19 7 18 bitrd NFinRRingMBMSiNjNkKiMj=Ak