Metamath Proof Explorer


Theorem cutbdaybnd

Description: An upper bound on the birthday of a surreal cut. (Contributed by Scott Fenton, 10-Aug-2024)

Ref Expression
Assertion cutbdaybnd ⊢ A ≪ s B ∧ O ∈ On ∧ bday A ∪ B ⊆ O → bday ⁡ A | s B ⊆ O

Proof

Step Hyp Ref Expression
1 etaslts ⊢ A ≪ s B ∧ O ∈ On ∧ bday A ∪ B ⊆ O → ∃ x ∈ No A ≪ s x ∧ x ≪ s B ∧ bday ⁡ x ⊆ O
2 simpl1 ⊢ A ≪ s B ∧ O ∈ On ∧ bday A ∪ B ⊆ O ∧ x ∈ No ∧ A ≪ s x ∧ x ≪ s B ∧ bday ⁡ x ⊆ O → A ≪ s B
3 cutbday ⊢ A ≪ s B → bday ⁡ A | s B = ⋂ bday y ∈ No | A ≪ s y ∧ y ≪ s B
4 2 3 syl ⊢ A ≪ s B ∧ O ∈ On ∧ bday A ∪ B ⊆ O ∧ x ∈ No ∧ A ≪ s x ∧ x ≪ s B ∧ bday ⁡ x ⊆ O → bday ⁡ A | s B = ⋂ bday y ∈ No | A ≪ s y ∧ y ≪ s B
5 bdayfn ⊢ bday Fn No
6 ssrab2 ⊢ y ∈ No | A ≪ s y ∧ y ≪ s B ⊆ No
7 sneq ⊢ y = x → y = x
8 7 breq2d ⊢ y = x → A ≪ s y ↔ A ≪ s x
9 7 breq1d ⊢ y = x → y ≪ s B ↔ x ≪ s B
10 8 9 anbi12d ⊢ y = x → A ≪ s y ∧ y ≪ s B ↔ A ≪ s x ∧ x ≪ s B
11 simprl ⊢ A ≪ s B ∧ O ∈ On ∧ bday A ∪ B ⊆ O ∧ x ∈ No ∧ A ≪ s x ∧ x ≪ s B ∧ bday ⁡ x ⊆ O → x ∈ No
12 simprr1 ⊢ A ≪ s B ∧ O ∈ On ∧ bday A ∪ B ⊆ O ∧ x ∈ No ∧ A ≪ s x ∧ x ≪ s B ∧ bday ⁡ x ⊆ O → A ≪ s x
13 simprr2 ⊢ A ≪ s B ∧ O ∈ On ∧ bday A ∪ B ⊆ O ∧ x ∈ No ∧ A ≪ s x ∧ x ≪ s B ∧ bday ⁡ x ⊆ O → x ≪ s B
14 12 13 jca ⊢ A ≪ s B ∧ O ∈ On ∧ bday A ∪ B ⊆ O ∧ x ∈ No ∧ A ≪ s x ∧ x ≪ s B ∧ bday ⁡ x ⊆ O → A ≪ s x ∧ x ≪ s B
15 10 11 14 elrabd ⊢ A ≪ s B ∧ O ∈ On ∧ bday A ∪ B ⊆ O ∧ x ∈ No ∧ A ≪ s x ∧ x ≪ s B ∧ bday ⁡ x ⊆ O → x ∈ y ∈ No | A ≪ s y ∧ y ≪ s B
16 fnfvima ⊢ bday Fn No ∧ y ∈ No | A ≪ s y ∧ y ≪ s B ⊆ No ∧ x ∈ y ∈ No | A ≪ s y ∧ y ≪ s B → bday ⁡ x ∈ bday y ∈ No | A ≪ s y ∧ y ≪ s B
17 5 6 15 16 mp3an12i ⊢ A ≪ s B ∧ O ∈ On ∧ bday A ∪ B ⊆ O ∧ x ∈ No ∧ A ≪ s x ∧ x ≪ s B ∧ bday ⁡ x ⊆ O → bday ⁡ x ∈ bday y ∈ No | A ≪ s y ∧ y ≪ s B
18 intss1 ⊢ bday ⁡ x ∈ bday y ∈ No | A ≪ s y ∧ y ≪ s B → ⋂ bday y ∈ No | A ≪ s y ∧ y ≪ s B ⊆ bday ⁡ x
19 17 18 syl ⊢ A ≪ s B ∧ O ∈ On ∧ bday A ∪ B ⊆ O ∧ x ∈ No ∧ A ≪ s x ∧ x ≪ s B ∧ bday ⁡ x ⊆ O → ⋂ bday y ∈ No | A ≪ s y ∧ y ≪ s B ⊆ bday ⁡ x
20 4 19 eqsstrd ⊢ A ≪ s B ∧ O ∈ On ∧ bday A ∪ B ⊆ O ∧ x ∈ No ∧ A ≪ s x ∧ x ≪ s B ∧ bday ⁡ x ⊆ O → bday ⁡ A | s B ⊆ bday ⁡ x
21 simprr3 ⊢ A ≪ s B ∧ O ∈ On ∧ bday A ∪ B ⊆ O ∧ x ∈ No ∧ A ≪ s x ∧ x ≪ s B ∧ bday ⁡ x ⊆ O → bday ⁡ x ⊆ O
22 20 21 sstrd ⊢ A ≪ s B ∧ O ∈ On ∧ bday A ∪ B ⊆ O ∧ x ∈ No ∧ A ≪ s x ∧ x ≪ s B ∧ bday ⁡ x ⊆ O → bday ⁡ A | s B ⊆ O
23 1 22 rexlimddv ⊢ A ≪ s B ∧ O ∈ On ∧ bday A ∪ B ⊆ O → bday ⁡ A | s B ⊆ O