Metamath Proof Explorer


Theorem dihglb

Description: Isomorphism H of a lattice glb. (Contributed by NM, 11-Apr-2014)

Ref Expression
Hypotheses dihglb.b ⊢ B = Base K
dihglb.g ⊢ G = glb ⁡ K
dihglb.h ⊢ H = LHyp ⁡ K
dihglb.i ⊢ I = DIsoH ⁡ K ⁡ W
Assertion dihglb ⊢ K ∈ HL ∧ W ∈ H ∧ S ⊆ B ∧ S ≠ ∅ → I ⁡ G ⁡ S = ⋂ x ∈ S I ⁡ x

Proof

Step Hyp Ref Expression
1 dihglb.b ⊢ B = Base K
2 dihglb.g ⊢ G = glb ⁡ K
3 dihglb.h ⊢ H = LHyp ⁡ K
4 dihglb.i ⊢ I = DIsoH ⁡ K ⁡ W
5 eqid ⊢ ≤ K = ≤ K
6 eqid ⊢ meet ⁡ K = meet ⁡ K
7 eqid ⊢ Atoms ⁡ K = Atoms ⁡ K
8 eqid ⊢ DVecH ⁡ K ⁡ W = DVecH ⁡ K ⁡ W
9 eqid ⊢ LSubSp ⁡ DVecH ⁡ K ⁡ W = LSubSp ⁡ DVecH ⁡ K ⁡ W
10 eqid ⊢ LSAtoms ⁡ DVecH ⁡ K ⁡ W = LSAtoms ⁡ DVecH ⁡ K ⁡ W
11 1 5 6 7 2 3 4 8 9 10 dihglblem6 ⊢ K ∈ HL ∧ W ∈ H ∧ S ⊆ B ∧ S ≠ ∅ → I ⁡ G ⁡ S = ⋂ x ∈ S I ⁡ x