Metamath Proof Explorer


Theorem dmrnxp

Description: A Cartesian product is the Cartesian product of its domain and range. (Contributed by Zhi Wang, 30-Oct-2025)

Ref Expression
Assertion dmrnxp ⊢ R = A × B → R = dom ⁡ R × ran ⁡ R

Proof

Step Hyp Ref Expression
1 simpl ⊢ R = A × B ∧ ¬ A ≠ ∅ → R = A × B
2 nne ⊢ ¬ A ≠ ∅ ↔ A = ∅
3 2 bilani ⊢ R = A × B ∧ ¬ A ≠ ∅ → A = ∅
4 3 xpeq1d ⊢ R = A × B ∧ ¬ A ≠ ∅ → A × B = ∅ × B
5 0xp ⊢ ∅ × B = ∅
6 4 5 eqtrdi ⊢ R = A × B ∧ ¬ A ≠ ∅ → A × B = ∅
7 1 6 eqtrd ⊢ R = A × B ∧ ¬ A ≠ ∅ → R = ∅
8 7 dmeqd ⊢ R = A × B ∧ ¬ A ≠ ∅ → dom ⁡ R = dom ⁡ ∅
9 dm0 ⊢ dom ⁡ ∅ = ∅
10 8 9 eqtrdi ⊢ R = A × B ∧ ¬ A ≠ ∅ → dom ⁡ R = ∅
11 7 rneqd ⊢ R = A × B ∧ ¬ A ≠ ∅ → ran ⁡ R = ran ⁡ ∅
12 rn0 ⊢ ran ⁡ ∅ = ∅
13 11 12 eqtrdi ⊢ R = A × B ∧ ¬ A ≠ ∅ → ran ⁡ R = ∅
14 10 13 xpeq12d ⊢ R = A × B ∧ ¬ A ≠ ∅ → dom ⁡ R × ran ⁡ R = ∅ × ∅
15 0xp ⊢ ∅ × ∅ = ∅
16 14 15 eqtrdi ⊢ R = A × B ∧ ¬ A ≠ ∅ → dom ⁡ R × ran ⁡ R = ∅
17 7 16 eqtr4d ⊢ R = A × B ∧ ¬ A ≠ ∅ → R = dom ⁡ R × ran ⁡ R
18 simpl ⊢ R = A × B ∧ ¬ B ≠ ∅ → R = A × B
19 nne ⊢ ¬ B ≠ ∅ ↔ B = ∅
20 19 bilani ⊢ R = A × B ∧ ¬ B ≠ ∅ → B = ∅
21 20 xpeq2d ⊢ R = A × B ∧ ¬ B ≠ ∅ → A × B = A × ∅
22 xp0 ⊢ A × ∅ = ∅
23 21 22 eqtrdi ⊢ R = A × B ∧ ¬ B ≠ ∅ → A × B = ∅
24 18 23 eqtrd ⊢ R = A × B ∧ ¬ B ≠ ∅ → R = ∅
25 24 dmeqd ⊢ R = A × B ∧ ¬ B ≠ ∅ → dom ⁡ R = dom ⁡ ∅
26 25 9 eqtrdi ⊢ R = A × B ∧ ¬ B ≠ ∅ → dom ⁡ R = ∅
27 24 rneqd ⊢ R = A × B ∧ ¬ B ≠ ∅ → ran ⁡ R = ran ⁡ ∅
28 27 12 eqtrdi ⊢ R = A × B ∧ ¬ B ≠ ∅ → ran ⁡ R = ∅
29 26 28 xpeq12d ⊢ R = A × B ∧ ¬ B ≠ ∅ → dom ⁡ R × ran ⁡ R = ∅ × ∅
30 29 15 eqtrdi ⊢ R = A × B ∧ ¬ B ≠ ∅ → dom ⁡ R × ran ⁡ R = ∅
31 24 30 eqtr4d ⊢ R = A × B ∧ ¬ B ≠ ∅ → R = dom ⁡ R × ran ⁡ R
32 simpl ⊢ R = A × B ∧ A ≠ ∅ ∧ B ≠ ∅ → R = A × B
33 32 dmeqd ⊢ R = A × B ∧ A ≠ ∅ ∧ B ≠ ∅ → dom ⁡ R = dom ⁡ A × B
34 dmxp ⊢ B ≠ ∅ → dom ⁡ A × B = A
35 34 ad2antll ⊢ R = A × B ∧ A ≠ ∅ ∧ B ≠ ∅ → dom ⁡ A × B = A
36 33 35 eqtrd ⊢ R = A × B ∧ A ≠ ∅ ∧ B ≠ ∅ → dom ⁡ R = A
37 32 rneqd ⊢ R = A × B ∧ A ≠ ∅ ∧ B ≠ ∅ → ran ⁡ R = ran ⁡ A × B
38 rnxp ⊢ A ≠ ∅ → ran ⁡ A × B = B
39 38 ad2antrl ⊢ R = A × B ∧ A ≠ ∅ ∧ B ≠ ∅ → ran ⁡ A × B = B
40 37 39 eqtrd ⊢ R = A × B ∧ A ≠ ∅ ∧ B ≠ ∅ → ran ⁡ R = B
41 36 40 xpeq12d ⊢ R = A × B ∧ A ≠ ∅ ∧ B ≠ ∅ → dom ⁡ R × ran ⁡ R = A × B
42 32 41 eqtr4d ⊢ R = A × B ∧ A ≠ ∅ ∧ B ≠ ∅ → R = dom ⁡ R × ran ⁡ R
43 17 31 42 pm2.61dda ⊢ R = A × B → R = dom ⁡ R × ran ⁡ R