Metamath Proof Explorer


Theorem dnwech

Description: Define a well-ordering from a choice function. (Contributed by Stefan O'Rear, 18-Jan-2015)

Ref Expression
Hypotheses dnnumch.f ⊢ F = recs ⁡ z ∈ V ⟼ G ⁡ A ∖ ran ⁡ z
dnnumch.a ⊢ φ → A ∈ V
dnnumch.g ⊢ φ → ∀ y ∈ 𝒫 A y ≠ ∅ → G ⁡ y ∈ y
dnwech.h ⊢ H = v w | ⋂ F -1 v ∈ ⋂ F -1 w
Assertion dnwech ⊢ φ → H We A

Proof

Step Hyp Ref Expression
1 dnnumch.f ⊢ F = recs ⁡ z ∈ V ⟼ G ⁡ A ∖ ran ⁡ z
2 dnnumch.a ⊢ φ → A ∈ V
3 dnnumch.g ⊢ φ → ∀ y ∈ 𝒫 A y ≠ ∅ → G ⁡ y ∈ y
4 dnwech.h ⊢ H = v w | ⋂ F -1 v ∈ ⋂ F -1 w
5 1 2 3 dnnumch3 ⊢ φ → x ∈ A ⟼ ⋂ F -1 x : A ⟶ 1-1 On
6 epweon ⊢ E We On
7 eqid ⊢ v w | x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w = v w | x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w
8 7 f1we ⊢ x ∈ A ⟼ ⋂ F -1 x : A ⟶ 1-1 On → E We On → v w | x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w We A
9 5 6 8 mpisyl ⊢ φ → v w | x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w We A
10 fvex ⊢ x ∈ A ⟼ ⋂ F -1 x ⁡ w ∈ V
11 10 epeli ⊢ x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w ↔ x ∈ A ⟼ ⋂ F -1 x ⁡ v ∈ x ∈ A ⟼ ⋂ F -1 x ⁡ w
12 1 2 3 dnnumch3lem ⊢ φ ∧ v ∈ A → x ∈ A ⟼ ⋂ F -1 x ⁡ v = ⋂ F -1 v
13 12 adantrr ⊢ φ ∧ v ∈ A ∧ w ∈ A → x ∈ A ⟼ ⋂ F -1 x ⁡ v = ⋂ F -1 v
14 1 2 3 dnnumch3lem ⊢ φ ∧ w ∈ A → x ∈ A ⟼ ⋂ F -1 x ⁡ w = ⋂ F -1 w
15 14 adantrl ⊢ φ ∧ v ∈ A ∧ w ∈ A → x ∈ A ⟼ ⋂ F -1 x ⁡ w = ⋂ F -1 w
16 13 15 eleq12d ⊢ φ ∧ v ∈ A ∧ w ∈ A → x ∈ A ⟼ ⋂ F -1 x ⁡ v ∈ x ∈ A ⟼ ⋂ F -1 x ⁡ w ↔ ⋂ F -1 v ∈ ⋂ F -1 w
17 11 16 bitr2id ⊢ φ ∧ v ∈ A ∧ w ∈ A → ⋂ F -1 v ∈ ⋂ F -1 w ↔ x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w
18 17 pm5.32da ⊢ φ → v ∈ A ∧ w ∈ A ∧ ⋂ F -1 v ∈ ⋂ F -1 w ↔ v ∈ A ∧ w ∈ A ∧ x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w
19 18 opabbidv ⊢ φ → v w | v ∈ A ∧ w ∈ A ∧ ⋂ F -1 v ∈ ⋂ F -1 w = v w | v ∈ A ∧ w ∈ A ∧ x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w
20 incom ⊢ H ∩ A × A = A × A ∩ H
21 df-xp ⊢ A × A = v w | v ∈ A ∧ w ∈ A
22 21 4 ineq12i ⊢ A × A ∩ H = v w | v ∈ A ∧ w ∈ A ∩ v w | ⋂ F -1 v ∈ ⋂ F -1 w
23 inopab ⊢ v w | v ∈ A ∧ w ∈ A ∩ v w | ⋂ F -1 v ∈ ⋂ F -1 w = v w | v ∈ A ∧ w ∈ A ∧ ⋂ F -1 v ∈ ⋂ F -1 w
24 20 22 23 3eqtri ⊢ H ∩ A × A = v w | v ∈ A ∧ w ∈ A ∧ ⋂ F -1 v ∈ ⋂ F -1 w
25 incom ⊢ v w | x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w ∩ A × A = A × A ∩ v w | x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w
26 21 ineq1i ⊢ A × A ∩ v w | x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w = v w | v ∈ A ∧ w ∈ A ∩ v w | x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w
27 inopab ⊢ v w | v ∈ A ∧ w ∈ A ∩ v w | x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w = v w | v ∈ A ∧ w ∈ A ∧ x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w
28 25 26 27 3eqtri ⊢ v w | x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w ∩ A × A = v w | v ∈ A ∧ w ∈ A ∧ x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w
29 19 24 28 3eqtr4g ⊢ φ → H ∩ A × A = v w | x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w ∩ A × A
30 weeq1 ⊢ H ∩ A × A = v w | x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w ∩ A × A → H ∩ A × A We A ↔ v w | x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w ∩ A × A We A
31 29 30 syl ⊢ φ → H ∩ A × A We A ↔ v w | x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w ∩ A × A We A
32 weinxp ⊢ H We A ↔ H ∩ A × A We A
33 weinxp ⊢ v w | x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w We A ↔ v w | x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w ∩ A × A We A
34 31 32 33 3bitr4g ⊢ φ → H We A ↔ v w | x ∈ A ⟼ ⋂ F -1 x ⁡ v E x ∈ A ⟼ ⋂ F -1 x ⁡ w We A
35 9 34 mpbird ⊢ φ → H We A