Metamath Proof Explorer


Theorem evennn02n

Description: A nonnegative integer is even iff it is twice another nonnegative integer. (Contributed by AV, 12-Aug-2021) (Proof shortened by AV, 10-Jul-2022)

Ref Expression
Assertion evennn02n ⊢ N ∈ ℕ 0 → 2 ∥ N ↔ ∃ n ∈ ℕ 0 2 ⁢ n = N

Proof

Step Hyp Ref Expression
1 eleq1 ⊢ 2 ⁢ n = N → 2 ⁢ n ∈ ℕ 0 ↔ N ∈ ℕ 0
2 simpr ⊢ 2 ⁢ n ∈ ℕ 0 ∧ n ∈ ℤ → n ∈ ℤ
3 2rp ⊢ 2 ∈ ℝ +
4 3 a1i ⊢ 2 ⁢ n ∈ ℕ 0 ∧ n ∈ ℤ → 2 ∈ ℝ +
5 zre ⊢ n ∈ ℤ → n ∈ ℝ
6 5 adantl ⊢ 2 ⁢ n ∈ ℕ 0 ∧ n ∈ ℤ → n ∈ ℝ
7 nn0ge0 ⊢ 2 ⁢ n ∈ ℕ 0 → 0 ≤ 2 ⁢ n
8 7 adantr ⊢ 2 ⁢ n ∈ ℕ 0 ∧ n ∈ ℤ → 0 ≤ 2 ⁢ n
9 4 6 8 prodge0rd ⊢ 2 ⁢ n ∈ ℕ 0 ∧ n ∈ ℤ → 0 ≤ n
10 elnn0z ⊢ n ∈ ℕ 0 ↔ n ∈ ℤ ∧ 0 ≤ n
11 2 9 10 sylanbrc ⊢ 2 ⁢ n ∈ ℕ 0 ∧ n ∈ ℤ → n ∈ ℕ 0
12 11 ex ⊢ 2 ⁢ n ∈ ℕ 0 → n ∈ ℤ → n ∈ ℕ 0
13 1 12 biimtrrdi ⊢ 2 ⁢ n = N → N ∈ ℕ 0 → n ∈ ℤ → n ∈ ℕ 0
14 13 com13 ⊢ n ∈ ℤ → N ∈ ℕ 0 → 2 ⁢ n = N → n ∈ ℕ 0
15 14 impcom ⊢ N ∈ ℕ 0 ∧ n ∈ ℤ → 2 ⁢ n = N → n ∈ ℕ 0
16 15 pm4.71rd ⊢ N ∈ ℕ 0 ∧ n ∈ ℤ → 2 ⁢ n = N ↔ n ∈ ℕ 0 ∧ 2 ⁢ n = N
17 16 bicomd ⊢ N ∈ ℕ 0 ∧ n ∈ ℤ → n ∈ ℕ 0 ∧ 2 ⁢ n = N ↔ 2 ⁢ n = N
18 17 rexbidva ⊢ N ∈ ℕ 0 → ∃ n ∈ ℤ n ∈ ℕ 0 ∧ 2 ⁢ n = N ↔ ∃ n ∈ ℤ 2 ⁢ n = N
19 nn0ssz ⊢ ℕ 0 ⊆ ℤ
20 rexss ⊢ ℕ 0 ⊆ ℤ → ∃ n ∈ ℕ 0 2 ⁢ n = N ↔ ∃ n ∈ ℤ n ∈ ℕ 0 ∧ 2 ⁢ n = N
21 19 20 mp1i ⊢ N ∈ ℕ 0 → ∃ n ∈ ℕ 0 2 ⁢ n = N ↔ ∃ n ∈ ℤ n ∈ ℕ 0 ∧ 2 ⁢ n = N
22 even2n ⊢ 2 ∥ N ↔ ∃ n ∈ ℤ 2 ⁢ n = N
23 22 a1i ⊢ N ∈ ℕ 0 → 2 ∥ N ↔ ∃ n ∈ ℤ 2 ⁢ n = N
24 18 21 23 3bitr4rd ⊢ N ∈ ℕ 0 → 2 ∥ N ↔ ∃ n ∈ ℕ 0 2 ⁢ n = N