Metamath Proof Explorer


Theorem f0rn0

Description: If there is no element in the range of a function, its domain must be empty. (Contributed by Alexander van der Vekens, 12-Jul-2018)

Ref Expression
Assertion f0rn0 ⊢ E : X ⟶ Y ∧ ¬ ∃ y ∈ Y y ∈ ran ⁡ E → X = ∅

Proof

Step Hyp Ref Expression
1 fdm ⊢ E : X ⟶ Y → dom ⁡ E = X
2 frn ⊢ E : X ⟶ Y → ran ⁡ E ⊆ Y
3 ralnex ⊢ ∀ y ∈ Y ¬ y ∈ ran ⁡ E ↔ ¬ ∃ y ∈ Y y ∈ ran ⁡ E
4 disj ⊢ Y ∩ ran ⁡ E = ∅ ↔ ∀ y ∈ Y ¬ y ∈ ran ⁡ E
5 dfss2 ⊢ ran ⁡ E ⊆ Y ↔ ran ⁡ E ∩ Y = ran ⁡ E
6 incom ⊢ ran ⁡ E ∩ Y = Y ∩ ran ⁡ E
7 6 eqeq1i ⊢ ran ⁡ E ∩ Y = ran ⁡ E ↔ Y ∩ ran ⁡ E = ran ⁡ E
8 eqtr2 ⊢ Y ∩ ran ⁡ E = ran ⁡ E ∧ Y ∩ ran ⁡ E = ∅ → ran ⁡ E = ∅
9 8 ex ⊢ Y ∩ ran ⁡ E = ran ⁡ E → Y ∩ ran ⁡ E = ∅ → ran ⁡ E = ∅
10 7 9 sylbi ⊢ ran ⁡ E ∩ Y = ran ⁡ E → Y ∩ ran ⁡ E = ∅ → ran ⁡ E = ∅
11 5 10 sylbi ⊢ ran ⁡ E ⊆ Y → Y ∩ ran ⁡ E = ∅ → ran ⁡ E = ∅
12 4 11 biimtrrid ⊢ ran ⁡ E ⊆ Y → ∀ y ∈ Y ¬ y ∈ ran ⁡ E → ran ⁡ E = ∅
13 3 12 biimtrrid ⊢ ran ⁡ E ⊆ Y → ¬ ∃ y ∈ Y y ∈ ran ⁡ E → ran ⁡ E = ∅
14 2 13 syl ⊢ E : X ⟶ Y → ¬ ∃ y ∈ Y y ∈ ran ⁡ E → ran ⁡ E = ∅
15 14 imp ⊢ E : X ⟶ Y ∧ ¬ ∃ y ∈ Y y ∈ ran ⁡ E → ran ⁡ E = ∅
16 15 adantl ⊢ dom ⁡ E = X ∧ E : X ⟶ Y ∧ ¬ ∃ y ∈ Y y ∈ ran ⁡ E → ran ⁡ E = ∅
17 dm0rn0 ⊢ dom ⁡ E = ∅ ↔ ran ⁡ E = ∅
18 16 17 sylibr ⊢ dom ⁡ E = X ∧ E : X ⟶ Y ∧ ¬ ∃ y ∈ Y y ∈ ran ⁡ E → dom ⁡ E = ∅
19 eqeq1 ⊢ X = dom ⁡ E → X = ∅ ↔ dom ⁡ E = ∅
20 19 eqcoms ⊢ dom ⁡ E = X → X = ∅ ↔ dom ⁡ E = ∅
21 20 adantr ⊢ dom ⁡ E = X ∧ E : X ⟶ Y ∧ ¬ ∃ y ∈ Y y ∈ ran ⁡ E → X = ∅ ↔ dom ⁡ E = ∅
22 18 21 mpbird ⊢ dom ⁡ E = X ∧ E : X ⟶ Y ∧ ¬ ∃ y ∈ Y y ∈ ran ⁡ E → X = ∅
23 22 exp32 ⊢ dom ⁡ E = X → E : X ⟶ Y → ¬ ∃ y ∈ Y y ∈ ran ⁡ E → X = ∅
24 1 23 mpcom ⊢ E : X ⟶ Y → ¬ ∃ y ∈ Y y ∈ ran ⁡ E → X = ∅
25 24 imp ⊢ E : X ⟶ Y ∧ ¬ ∃ y ∈ Y y ∈ ran ⁡ E → X = ∅