Metamath Proof Explorer


Theorem f1ghm0to0

Description: If a group homomorphism F is injective, it maps the zero of one group (and only the zero) to the zero of the other group. (Contributed by AV, 24-Oct-2019) (Revised by Thierry Arnoux, 13-May-2023)

Ref Expression
Hypotheses f1ghm0to0.a ⊢ A = Base R
f1ghm0to0.b ⊢ B = Base S
f1ghm0to0.n ⊢ N = 0 R
f1ghm0to0.0 ⊢ 0 ˙ = 0 S
Assertion f1ghm0to0 ⊢ F ∈ R GrpHom S ∧ F : A ⟶ 1-1 B ∧ X ∈ A → F ⁡ X = 0 ˙ ↔ X = N

Proof

Step Hyp Ref Expression
1 f1ghm0to0.a ⊢ A = Base R
2 f1ghm0to0.b ⊢ B = Base S
3 f1ghm0to0.n ⊢ N = 0 R
4 f1ghm0to0.0 ⊢ 0 ˙ = 0 S
5 3 4 ghmid ⊢ F ∈ R GrpHom S → F ⁡ N = 0 ˙
6 5 3ad2ant1 ⊢ F ∈ R GrpHom S ∧ F : A ⟶ 1-1 B ∧ X ∈ A → F ⁡ N = 0 ˙
7 6 eqeq2d ⊢ F ∈ R GrpHom S ∧ F : A ⟶ 1-1 B ∧ X ∈ A → F ⁡ X = F ⁡ N ↔ F ⁡ X = 0 ˙
8 simp2 ⊢ F ∈ R GrpHom S ∧ F : A ⟶ 1-1 B ∧ X ∈ A → F : A ⟶ 1-1 B
9 simp3 ⊢ F ∈ R GrpHom S ∧ F : A ⟶ 1-1 B ∧ X ∈ A → X ∈ A
10 ghmgrp1 ⊢ F ∈ R GrpHom S → R ∈ Grp
11 1 3 grpidcl ⊢ R ∈ Grp → N ∈ A
12 10 11 syl ⊢ F ∈ R GrpHom S → N ∈ A
13 12 3ad2ant1 ⊢ F ∈ R GrpHom S ∧ F : A ⟶ 1-1 B ∧ X ∈ A → N ∈ A
14 f1veqaeq ⊢ F : A ⟶ 1-1 B ∧ X ∈ A ∧ N ∈ A → F ⁡ X = F ⁡ N → X = N
15 8 9 13 14 syl12anc ⊢ F ∈ R GrpHom S ∧ F : A ⟶ 1-1 B ∧ X ∈ A → F ⁡ X = F ⁡ N → X = N
16 7 15 sylbird ⊢ F ∈ R GrpHom S ∧ F : A ⟶ 1-1 B ∧ X ∈ A → F ⁡ X = 0 ˙ → X = N
17 fveq2 ⊢ X = N → F ⁡ X = F ⁡ N
18 17 6 sylan9eqr ⊢ F ∈ R GrpHom S ∧ F : A ⟶ 1-1 B ∧ X ∈ A ∧ X = N → F ⁡ X = 0 ˙
19 18 ex ⊢ F ∈ R GrpHom S ∧ F : A ⟶ 1-1 B ∧ X ∈ A → X = N → F ⁡ X = 0 ˙
20 16 19 impbid ⊢ F ∈ R GrpHom S ∧ F : A ⟶ 1-1 B ∧ X ∈ A → F ⁡ X = 0 ˙ ↔ X = N