Metamath Proof Explorer


Theorem finxpreclem5

Description: Lemma for ^^ recursion theorems. (Contributed by ML, 24-Oct-2020)

Ref Expression
Hypothesis finxpreclem5.1 ⊢ F = n ∈ ω , x ∈ V ⟼ if n = 1 𝑜 ∧ x ∈ U ∅ if x ∈ V × U ⋃ n 1 st ⁡ x n x
Assertion finxpreclem5 ⊢ n ∈ ω ∧ 1 𝑜 ∈ n → ¬ x ∈ V × U → F ⁡ n x = n x

Proof

Step Hyp Ref Expression
1 finxpreclem5.1 ⊢ F = n ∈ ω , x ∈ V ⟼ if n = 1 𝑜 ∧ x ∈ U ∅ if x ∈ V × U ⋃ n 1 st ⁡ x n x
2 df-ov ⊢ n F x = F ⁡ n x
3 vex ⊢ x ∈ V
4 0ex ⊢ ∅ ∈ V
5 opex ⊢ ⋃ n 1 st ⁡ x ∈ V
6 opex ⊢ n x ∈ V
7 5 6 ifex ⊢ if x ∈ V × U ⋃ n 1 st ⁡ x n x ∈ V
8 4 7 ifex ⊢ if n = 1 𝑜 ∧ x ∈ U ∅ if x ∈ V × U ⋃ n 1 st ⁡ x n x ∈ V
9 1 ovmpt4g ⊢ n ∈ ω ∧ x ∈ V ∧ if n = 1 𝑜 ∧ x ∈ U ∅ if x ∈ V × U ⋃ n 1 st ⁡ x n x ∈ V → n F x = if n = 1 𝑜 ∧ x ∈ U ∅ if x ∈ V × U ⋃ n 1 st ⁡ x n x
10 3 8 9 mp3an23 ⊢ n ∈ ω → n F x = if n = 1 𝑜 ∧ x ∈ U ∅ if x ∈ V × U ⋃ n 1 st ⁡ x n x
11 10 ad2antrr ⊢ n ∈ ω ∧ 1 𝑜 ∈ n ∧ ¬ x ∈ V × U → n F x = if n = 1 𝑜 ∧ x ∈ U ∅ if x ∈ V × U ⋃ n 1 st ⁡ x n x
12 1on ⊢ 1 𝑜 ∈ On
13 12 onirri ⊢ ¬ 1 𝑜 ∈ 1 𝑜
14 eleq2 ⊢ n = 1 𝑜 → 1 𝑜 ∈ n ↔ 1 𝑜 ∈ 1 𝑜
15 13 14 mtbiri ⊢ n = 1 𝑜 → ¬ 1 𝑜 ∈ n
16 15 con2i ⊢ 1 𝑜 ∈ n → ¬ n = 1 𝑜
17 16 intnanrd ⊢ 1 𝑜 ∈ n → ¬ n = 1 𝑜 ∧ x ∈ U
18 17 iffalsed ⊢ 1 𝑜 ∈ n → if n = 1 𝑜 ∧ x ∈ U ∅ if x ∈ V × U ⋃ n 1 st ⁡ x n x = if x ∈ V × U ⋃ n 1 st ⁡ x n x
19 18 adantl ⊢ n ∈ ω ∧ 1 𝑜 ∈ n → if n = 1 𝑜 ∧ x ∈ U ∅ if x ∈ V × U ⋃ n 1 st ⁡ x n x = if x ∈ V × U ⋃ n 1 st ⁡ x n x
20 iffalse ⊢ ¬ x ∈ V × U → if x ∈ V × U ⋃ n 1 st ⁡ x n x = n x
21 19 20 sylan9eq ⊢ n ∈ ω ∧ 1 𝑜 ∈ n ∧ ¬ x ∈ V × U → if n = 1 𝑜 ∧ x ∈ U ∅ if x ∈ V × U ⋃ n 1 st ⁡ x n x = n x
22 11 21 eqtrd ⊢ n ∈ ω ∧ 1 𝑜 ∈ n ∧ ¬ x ∈ V × U → n F x = n x
23 2 22 eqtr3id ⊢ n ∈ ω ∧ 1 𝑜 ∈ n ∧ ¬ x ∈ V × U → F ⁡ n x = n x
24 23 ex ⊢ n ∈ ω ∧ 1 𝑜 ∈ n → ¬ x ∈ V × U → F ⁡ n x = n x