Metamath Proof Explorer


Theorem fmtnorec1

Description: The first recurrence relation for Fermat numbers, see Wikipedia "Fermat number", https://en.wikipedia.org/wiki/Fermat_number#Basic_properties , 22-Jul-2021. (Contributed by AV, 22-Jul-2021)

Ref Expression
Assertion fmtnorec1 ⊢ N ∈ ℕ 0 → FermatNo ⁡ N + 1 = FermatNo ⁡ N − 1 2 + 1

Proof

Step Hyp Ref Expression
1 peano2nn0 ⊢ N ∈ ℕ 0 → N + 1 ∈ ℕ 0
2 fmtno ⊢ N + 1 ∈ ℕ 0 → FermatNo ⁡ N + 1 = 2 2 N + 1 + 1
3 1 2 syl ⊢ N ∈ ℕ 0 → FermatNo ⁡ N + 1 = 2 2 N + 1 + 1
4 2nn0 ⊢ 2 ∈ ℕ 0
5 nn0expcl ⊢ 2 ∈ ℕ 0 ∧ N ∈ ℕ 0 → 2 N ∈ ℕ 0
6 4 5 mpan ⊢ N ∈ ℕ 0 → 2 N ∈ ℕ 0
7 nn0expcl ⊢ 2 ∈ ℕ 0 ∧ 2 N ∈ ℕ 0 → 2 2 N ∈ ℕ 0
8 7 nn0cnd ⊢ 2 ∈ ℕ 0 ∧ 2 N ∈ ℕ 0 → 2 2 N ∈ ℂ
9 4 6 8 sylancr ⊢ N ∈ ℕ 0 → 2 2 N ∈ ℂ
10 pncan1 ⊢ 2 2 N ∈ ℂ → 2 2 N + 1 - 1 = 2 2 N
11 9 10 syl ⊢ N ∈ ℕ 0 → 2 2 N + 1 - 1 = 2 2 N
12 11 oveq1d ⊢ N ∈ ℕ 0 → 2 2 N + 1 - 1 2 = 2 2 N 2
13 2cnne0 ⊢ 2 ∈ ℂ ∧ 2 ≠ 0
14 6 nn0zd ⊢ N ∈ ℕ 0 → 2 N ∈ ℤ
15 2z ⊢ 2 ∈ ℤ
16 14 15 jctir ⊢ N ∈ ℕ 0 → 2 N ∈ ℤ ∧ 2 ∈ ℤ
17 expmulz ⊢ 2 ∈ ℂ ∧ 2 ≠ 0 ∧ 2 N ∈ ℤ ∧ 2 ∈ ℤ → 2 2 N ⋅ 2 = 2 2 N 2
18 13 16 17 sylancr ⊢ N ∈ ℕ 0 → 2 2 N ⋅ 2 = 2 2 N 2
19 2cn ⊢ 2 ∈ ℂ
20 2ne0 ⊢ 2 ≠ 0
21 nn0z ⊢ N ∈ ℕ 0 → N ∈ ℤ
22 expp1z ⊢ 2 ∈ ℂ ∧ 2 ≠ 0 ∧ N ∈ ℤ → 2 N + 1 = 2 N ⋅ 2
23 19 20 21 22 mp3an12i ⊢ N ∈ ℕ 0 → 2 N + 1 = 2 N ⋅ 2
24 23 eqcomd ⊢ N ∈ ℕ 0 → 2 N ⋅ 2 = 2 N + 1
25 24 oveq2d ⊢ N ∈ ℕ 0 → 2 2 N ⋅ 2 = 2 2 N + 1
26 12 18 25 3eqtr2rd ⊢ N ∈ ℕ 0 → 2 2 N + 1 = 2 2 N + 1 - 1 2
27 26 oveq1d ⊢ N ∈ ℕ 0 → 2 2 N + 1 + 1 = 2 2 N + 1 - 1 2 + 1
28 fmtno ⊢ N ∈ ℕ 0 → FermatNo ⁡ N = 2 2 N + 1
29 28 eqcomd ⊢ N ∈ ℕ 0 → 2 2 N + 1 = FermatNo ⁡ N
30 29 oveq1d ⊢ N ∈ ℕ 0 → 2 2 N + 1 - 1 = FermatNo ⁡ N − 1
31 30 oveq1d ⊢ N ∈ ℕ 0 → 2 2 N + 1 - 1 2 = FermatNo ⁡ N − 1 2
32 31 oveq1d ⊢ N ∈ ℕ 0 → 2 2 N + 1 - 1 2 + 1 = FermatNo ⁡ N − 1 2 + 1
33 3 27 32 3eqtrd ⊢ N ∈ ℕ 0 → FermatNo ⁡ N + 1 = FermatNo ⁡ N − 1 2 + 1