Metamath Proof Explorer


Theorem fprod0

Description: A finite product with a zero term is zero. (Contributed by Glauco Siliprandi, 5-Apr-2020)

Ref Expression
Hypotheses fprod0.kph ⊢ Ⅎ k φ
fprod0.kc ⊢ Ⅎ _ k C
fprod0.a ⊢ φ → A ∈ Fin
fprod0.b ⊢ φ ∧ k ∈ A → B ∈ ℂ
fprod0.bc ⊢ k = K → B = C
fprod0.k ⊢ φ → K ∈ A
fprod0.c ⊢ φ → C = 0
Assertion fprod0 ⊢ φ → ∏ k ∈ A B = 0

Proof

Step Hyp Ref Expression
1 fprod0.kph ⊢ Ⅎ k φ
2 fprod0.kc ⊢ Ⅎ _ k C
3 fprod0.a ⊢ φ → A ∈ Fin
4 fprod0.b ⊢ φ ∧ k ∈ A → B ∈ ℂ
5 fprod0.bc ⊢ k = K → B = C
6 fprod0.k ⊢ φ → K ∈ A
7 fprod0.c ⊢ φ → C = 0
8 2 a1i ⊢ φ → Ⅎ _ k C
9 5 adantl ⊢ φ ∧ k = K → B = C
10 1 8 3 4 6 9 fprodsplit1f ⊢ φ → ∏ k ∈ A B = C ⁢ ∏ k ∈ A ∖ K B
11 7 oveq1d ⊢ φ → C ⁢ ∏ k ∈ A ∖ K B = 0 ⋅ ∏ k ∈ A ∖ K B
12 diffi ⊢ A ∈ Fin → A ∖ K ∈ Fin
13 3 12 syl ⊢ φ → A ∖ K ∈ Fin
14 simpl ⊢ φ ∧ k ∈ A ∖ K → φ
15 eldifi ⊢ k ∈ A ∖ K → k ∈ A
16 15 adantl ⊢ φ ∧ k ∈ A ∖ K → k ∈ A
17 14 16 4 syl2anc ⊢ φ ∧ k ∈ A ∖ K → B ∈ ℂ
18 1 13 17 fprodclf ⊢ φ → ∏ k ∈ A ∖ K B ∈ ℂ
19 18 mul02d ⊢ φ → 0 ⋅ ∏ k ∈ A ∖ K B = 0
20 10 11 19 3eqtrd ⊢ φ → ∏ k ∈ A B = 0