Metamath Proof Explorer


Theorem fpwwe2lem4

Description: Lemma for fpwwe2 . (Contributed by Mario Carneiro, 15-May-2015) (Revised by AV, 20-Jul-2024) (Proof shortened by Matthew House, 10-Sep-2025)

Ref Expression
Hypotheses fpwwe2.1 ⊢ W = x r | x ⊆ A ∧ r ⊆ x × x ∧ r We x ∧ ∀ y ∈ x [˙ r -1 y / u]˙ u F r ∩ u × u = y
fpwwe2.2 ⊢ φ → A ∈ V
fpwwe2.3 ⊢ φ ∧ x ⊆ A ∧ r ⊆ x × x ∧ r We x → x F r ∈ A
Assertion fpwwe2lem4 ⊢ φ ∧ X ⊆ A ∧ R ⊆ X × X ∧ R We X → X F R ∈ A

Proof

Step Hyp Ref Expression
1 fpwwe2.1 ⊢ W = x r | x ⊆ A ∧ r ⊆ x × x ∧ r We x ∧ ∀ y ∈ x [˙ r -1 y / u]˙ u F r ∩ u × u = y
2 fpwwe2.2 ⊢ φ → A ∈ V
3 fpwwe2.3 ⊢ φ ∧ x ⊆ A ∧ r ⊆ x × x ∧ r We x → x F r ∈ A
4 2 adantr ⊢ φ ∧ X ⊆ A ∧ R ⊆ X × X ∧ R We X → A ∈ V
5 simpr1 ⊢ φ ∧ X ⊆ A ∧ R ⊆ X × X ∧ R We X → X ⊆ A
6 4 5 ssexd ⊢ φ ∧ X ⊆ A ∧ R ⊆ X × X ∧ R We X → X ∈ V
7 6 6 xpexd ⊢ φ ∧ X ⊆ A ∧ R ⊆ X × X ∧ R We X → X × X ∈ V
8 simpr2 ⊢ φ ∧ X ⊆ A ∧ R ⊆ X × X ∧ R We X → R ⊆ X × X
9 7 8 ssexd ⊢ φ ∧ X ⊆ A ∧ R ⊆ X × X ∧ R We X → R ∈ V
10 simpl ⊢ x = X ∧ r = R → x = X
11 10 sseq1d ⊢ x = X ∧ r = R → x ⊆ A ↔ X ⊆ A
12 simpr ⊢ x = X ∧ r = R → r = R
13 10 sqxpeqd ⊢ x = X ∧ r = R → x × x = X × X
14 12 13 sseq12d ⊢ x = X ∧ r = R → r ⊆ x × x ↔ R ⊆ X × X
15 12 10 weeq12d ⊢ x = X ∧ r = R → r We x ↔ R We X
16 11 14 15 3anbi123d ⊢ x = X ∧ r = R → x ⊆ A ∧ r ⊆ x × x ∧ r We x ↔ X ⊆ A ∧ R ⊆ X × X ∧ R We X
17 oveq12 ⊢ x = X ∧ r = R → x F r = X F R
18 17 eleq1d ⊢ x = X ∧ r = R → x F r ∈ A ↔ X F R ∈ A
19 16 18 imbi12d ⊢ x = X ∧ r = R → x ⊆ A ∧ r ⊆ x × x ∧ r We x → x F r ∈ A ↔ X ⊆ A ∧ R ⊆ X × X ∧ R We X → X F R ∈ A
20 3 ex ⊢ φ → x ⊆ A ∧ r ⊆ x × x ∧ r We x → x F r ∈ A
21 20 adantr ⊢ φ ∧ X ⊆ A ∧ R ⊆ X × X ∧ R We X → x ⊆ A ∧ r ⊆ x × x ∧ r We x → x F r ∈ A
22 6 9 19 21 vtocl2d ⊢ φ ∧ X ⊆ A ∧ R ⊆ X × X ∧ R We X → X ⊆ A ∧ R ⊆ X × X ∧ R We X → X F R ∈ A
23 22 syldbl2 ⊢ φ ∧ X ⊆ A ∧ R ⊆ X × X ∧ R We X → X F R ∈ A