Metamath Proof Explorer


Theorem frlmvscafval

Description: Scalar multiplication in a free module. (Contributed by Stefan O'Rear, 1-Feb-2015) (Revised by Stefan O'Rear, 6-May-2015)

Ref Expression
Hypotheses frlmvscafval.y ⊢ Y = R freeLMod I
frlmvscafval.b ⊢ B = Base Y
frlmvscafval.k ⊢ K = Base R
frlmvscafval.i ⊢ φ → I ∈ W
frlmvscafval.a ⊢ φ → A ∈ K
frlmvscafval.x ⊢ φ → X ∈ B
frlmvscafval.v ⊢ ∙ ˙ = ⋅ Y
frlmvscafval.t ⊢ · ˙ = ⋅ R
Assertion frlmvscafval ⊢ φ → A ∙ ˙ X = I × A · ˙ f X

Proof

Step Hyp Ref Expression
1 frlmvscafval.y ⊢ Y = R freeLMod I
2 frlmvscafval.b ⊢ B = Base Y
3 frlmvscafval.k ⊢ K = Base R
4 frlmvscafval.i ⊢ φ → I ∈ W
5 frlmvscafval.a ⊢ φ → A ∈ K
6 frlmvscafval.x ⊢ φ → X ∈ B
7 frlmvscafval.v ⊢ ∙ ˙ = ⋅ Y
8 frlmvscafval.t ⊢ · ˙ = ⋅ R
9 1 2 frlmrcl ⊢ X ∈ B → R ∈ V
10 6 9 syl ⊢ φ → R ∈ V
11 1 2 frlmpws ⊢ R ∈ V ∧ I ∈ W → Y = ringLMod ⁡ R ↑ 𝑠 I ↾ 𝑠 B
12 10 4 11 syl2anc ⊢ φ → Y = ringLMod ⁡ R ↑ 𝑠 I ↾ 𝑠 B
13 12 fveq2d ⊢ φ → ⋅ Y = ⋅ ringLMod ⁡ R ↑ 𝑠 I ↾ 𝑠 B
14 2 fvexi ⊢ B ∈ V
15 eqid ⊢ ringLMod ⁡ R ↑ 𝑠 I ↾ 𝑠 B = ringLMod ⁡ R ↑ 𝑠 I ↾ 𝑠 B
16 eqid ⊢ ⋅ ringLMod ⁡ R ↑ 𝑠 I = ⋅ ringLMod ⁡ R ↑ 𝑠 I
17 15 16 ressvsca ⊢ B ∈ V → ⋅ ringLMod ⁡ R ↑ 𝑠 I = ⋅ ringLMod ⁡ R ↑ 𝑠 I ↾ 𝑠 B
18 14 17 ax-mp ⊢ ⋅ ringLMod ⁡ R ↑ 𝑠 I = ⋅ ringLMod ⁡ R ↑ 𝑠 I ↾ 𝑠 B
19 13 7 18 3eqtr4g ⊢ φ → ∙ ˙ = ⋅ ringLMod ⁡ R ↑ 𝑠 I
20 19 oveqd ⊢ φ → A ∙ ˙ X = A ⋅ ringLMod ⁡ R ↑ 𝑠 I X
21 eqid ⊢ ringLMod ⁡ R ↑ 𝑠 I = ringLMod ⁡ R ↑ 𝑠 I
22 eqid ⊢ Base ringLMod ⁡ R ↑ 𝑠 I = Base ringLMod ⁡ R ↑ 𝑠 I
23 rlmvsca ⊢ ⋅ R = ⋅ ringLMod ⁡ R
24 8 23 eqtri ⊢ · ˙ = ⋅ ringLMod ⁡ R
25 eqid ⊢ Scalar ⁡ ringLMod ⁡ R = Scalar ⁡ ringLMod ⁡ R
26 eqid ⊢ Base Scalar ⁡ ringLMod ⁡ R = Base Scalar ⁡ ringLMod ⁡ R
27 fvexd ⊢ φ → ringLMod ⁡ R ∈ V
28 rlmsca ⊢ R ∈ V → R = Scalar ⁡ ringLMod ⁡ R
29 10 28 syl ⊢ φ → R = Scalar ⁡ ringLMod ⁡ R
30 29 fveq2d ⊢ φ → Base R = Base Scalar ⁡ ringLMod ⁡ R
31 3 30 eqtrid ⊢ φ → K = Base Scalar ⁡ ringLMod ⁡ R
32 5 31 eleqtrd ⊢ φ → A ∈ Base Scalar ⁡ ringLMod ⁡ R
33 12 fveq2d ⊢ φ → Base Y = Base ringLMod ⁡ R ↑ 𝑠 I ↾ 𝑠 B
34 2 33 eqtrid ⊢ φ → B = Base ringLMod ⁡ R ↑ 𝑠 I ↾ 𝑠 B
35 15 22 ressbasss ⊢ Base ringLMod ⁡ R ↑ 𝑠 I ↾ 𝑠 B ⊆ Base ringLMod ⁡ R ↑ 𝑠 I
36 34 35 eqsstrdi ⊢ φ → B ⊆ Base ringLMod ⁡ R ↑ 𝑠 I
37 36 6 sseldd ⊢ φ → X ∈ Base ringLMod ⁡ R ↑ 𝑠 I
38 21 22 24 16 25 26 27 4 32 37 pwsvscafval ⊢ φ → A ⋅ ringLMod ⁡ R ↑ 𝑠 I X = I × A · ˙ f X
39 20 38 eqtrd ⊢ φ → A ∙ ˙ X = I × A · ˙ f X