Metamath Proof Explorer


Theorem funcnvtp

Description: The converse triple of ordered pairs is a function if the second members are pairwise different. Note that the second members need not be sets. (Contributed by AV, 23-Jan-2021)

Ref Expression
Assertion funcnvtp ⊢ A ∈ U ∧ C ∈ V ∧ E ∈ W ∧ B ≠ D ∧ B ≠ F ∧ D ≠ F → Fun ⁡ A B C D E F -1

Proof

Step Hyp Ref Expression
1 simp1 ⊢ A ∈ U ∧ C ∈ V ∧ E ∈ W → A ∈ U
2 simp2 ⊢ A ∈ U ∧ C ∈ V ∧ E ∈ W → C ∈ V
3 simp1 ⊢ B ≠ D ∧ B ≠ F ∧ D ≠ F → B ≠ D
4 funcnvpr ⊢ A ∈ U ∧ C ∈ V ∧ B ≠ D → Fun ⁡ A B C D -1
5 1 2 3 4 syl2an3an ⊢ A ∈ U ∧ C ∈ V ∧ E ∈ W ∧ B ≠ D ∧ B ≠ F ∧ D ≠ F → Fun ⁡ A B C D -1
6 funcnvsn ⊢ Fun ⁡ E F -1
7 6 a1i ⊢ A ∈ U ∧ C ∈ V ∧ E ∈ W ∧ B ≠ D ∧ B ≠ F ∧ D ≠ F → Fun ⁡ E F -1
8 df-rn ⊢ ran ⁡ A B C D = dom ⁡ A B C D -1
9 rnpropg ⊢ A ∈ U ∧ C ∈ V → ran ⁡ A B C D = B D
10 8 9 eqtr3id ⊢ A ∈ U ∧ C ∈ V → dom ⁡ A B C D -1 = B D
11 10 3adant3 ⊢ A ∈ U ∧ C ∈ V ∧ E ∈ W → dom ⁡ A B C D -1 = B D
12 df-rn ⊢ ran ⁡ E F = dom ⁡ E F -1
13 rnsnopg ⊢ E ∈ W → ran ⁡ E F = F
14 12 13 eqtr3id ⊢ E ∈ W → dom ⁡ E F -1 = F
15 14 3ad2ant3 ⊢ A ∈ U ∧ C ∈ V ∧ E ∈ W → dom ⁡ E F -1 = F
16 11 15 ineq12d ⊢ A ∈ U ∧ C ∈ V ∧ E ∈ W → dom ⁡ A B C D -1 ∩ dom ⁡ E F -1 = B D ∩ F
17 disjprsn ⊢ B ≠ F ∧ D ≠ F → B D ∩ F = ∅
18 17 3adant1 ⊢ B ≠ D ∧ B ≠ F ∧ D ≠ F → B D ∩ F = ∅
19 16 18 sylan9eq ⊢ A ∈ U ∧ C ∈ V ∧ E ∈ W ∧ B ≠ D ∧ B ≠ F ∧ D ≠ F → dom ⁡ A B C D -1 ∩ dom ⁡ E F -1 = ∅
20 funun ⊢ Fun ⁡ A B C D -1 ∧ Fun ⁡ E F -1 ∧ dom ⁡ A B C D -1 ∩ dom ⁡ E F -1 = ∅ → Fun ⁡ A B C D -1 ∪ E F -1
21 5 7 19 20 syl21anc ⊢ A ∈ U ∧ C ∈ V ∧ E ∈ W ∧ B ≠ D ∧ B ≠ F ∧ D ≠ F → Fun ⁡ A B C D -1 ∪ E F -1
22 df-tp ⊢ A B C D E F = A B C D ∪ E F
23 22 cnveqi ⊢ A B C D E F -1 = A B C D ∪ E F -1
24 cnvun ⊢ A B C D ∪ E F -1 = A B C D -1 ∪ E F -1
25 23 24 eqtri ⊢ A B C D E F -1 = A B C D -1 ∪ E F -1
26 25 funeqi ⊢ Fun ⁡ A B C D E F -1 ↔ Fun ⁡ A B C D -1 ∪ E F -1
27 21 26 sylibr ⊢ A ∈ U ∧ C ∈ V ∧ E ∈ W ∧ B ≠ D ∧ B ≠ F ∧ D ≠ F → Fun ⁡ A B C D E F -1