Metamath Proof Explorer


Theorem geoserg

Description: The value of the finite geometric series A ^ M + A ^ ( M + 1 ) + ... + A ^ ( N - 1 ) . (Contributed by Mario Carneiro, 2-May-2016)

Ref Expression
Hypotheses geoserg.1 ⊢ φ → A ∈ ℂ
geoserg.2 ⊢ φ → A ≠ 1
geoserg.3 ⊢ φ → M ∈ ℕ 0
geoserg.4 ⊢ φ → N ∈ ℤ ≥ M
Assertion geoserg ⊢ φ → ∑ k ∈ M ..^ N A k = A M − A N 1 − A

Proof

Step Hyp Ref Expression
1 geoserg.1 ⊢ φ → A ∈ ℂ
2 geoserg.2 ⊢ φ → A ≠ 1
3 geoserg.3 ⊢ φ → M ∈ ℕ 0
4 geoserg.4 ⊢ φ → N ∈ ℤ ≥ M
5 fzofi ⊢ M ..^ N ∈ Fin
6 5 a1i ⊢ φ → M ..^ N ∈ Fin
7 ax-1cn ⊢ 1 ∈ ℂ
8 subcl ⊢ 1 ∈ ℂ ∧ A ∈ ℂ → 1 − A ∈ ℂ
9 7 1 8 sylancr ⊢ φ → 1 − A ∈ ℂ
10 1 adantr ⊢ φ ∧ k ∈ M ..^ N → A ∈ ℂ
11 elfzouz ⊢ k ∈ M ..^ N → k ∈ ℤ ≥ M
12 eluznn0 ⊢ M ∈ ℕ 0 ∧ k ∈ ℤ ≥ M → k ∈ ℕ 0
13 3 11 12 syl2an ⊢ φ ∧ k ∈ M ..^ N → k ∈ ℕ 0
14 10 13 expcld ⊢ φ ∧ k ∈ M ..^ N → A k ∈ ℂ
15 6 9 14 fsummulc1 ⊢ φ → ∑ k ∈ M ..^ N A k ⁢ 1 − A = ∑ k ∈ M ..^ N A k ⁢ 1 − A
16 7 a1i ⊢ φ ∧ k ∈ M ..^ N → 1 ∈ ℂ
17 14 16 10 subdid ⊢ φ ∧ k ∈ M ..^ N → A k ⁢ 1 − A = A k ⋅ 1 − A k ⁢ A
18 14 mulridd ⊢ φ ∧ k ∈ M ..^ N → A k ⋅ 1 = A k
19 10 13 expp1d ⊢ φ ∧ k ∈ M ..^ N → A k + 1 = A k ⁢ A
20 19 eqcomd ⊢ φ ∧ k ∈ M ..^ N → A k ⁢ A = A k + 1
21 18 20 oveq12d ⊢ φ ∧ k ∈ M ..^ N → A k ⋅ 1 − A k ⁢ A = A k − A k + 1
22 17 21 eqtrd ⊢ φ ∧ k ∈ M ..^ N → A k ⁢ 1 − A = A k − A k + 1
23 22 sumeq2dv ⊢ φ → ∑ k ∈ M ..^ N A k ⁢ 1 − A = ∑ k ∈ M ..^ N A k − A k + 1
24 oveq2 ⊢ j = k → A j = A k
25 oveq2 ⊢ j = k + 1 → A j = A k + 1
26 oveq2 ⊢ j = M → A j = A M
27 oveq2 ⊢ j = N → A j = A N
28 1 adantr ⊢ φ ∧ j ∈ M … N → A ∈ ℂ
29 elfzuz ⊢ j ∈ M … N → j ∈ ℤ ≥ M
30 eluznn0 ⊢ M ∈ ℕ 0 ∧ j ∈ ℤ ≥ M → j ∈ ℕ 0
31 3 29 30 syl2an ⊢ φ ∧ j ∈ M … N → j ∈ ℕ 0
32 28 31 expcld ⊢ φ ∧ j ∈ M … N → A j ∈ ℂ
33 24 25 26 27 4 32 telfsumo ⊢ φ → ∑ k ∈ M ..^ N A k − A k + 1 = A M − A N
34 15 23 33 3eqtrrd ⊢ φ → A M − A N = ∑ k ∈ M ..^ N A k ⁢ 1 − A
35 1 3 expcld ⊢ φ → A M ∈ ℂ
36 eluznn0 ⊢ M ∈ ℕ 0 ∧ N ∈ ℤ ≥ M → N ∈ ℕ 0
37 3 4 36 syl2anc ⊢ φ → N ∈ ℕ 0
38 1 37 expcld ⊢ φ → A N ∈ ℂ
39 35 38 subcld ⊢ φ → A M − A N ∈ ℂ
40 6 14 fsumcl ⊢ φ → ∑ k ∈ M ..^ N A k ∈ ℂ
41 2 necomd ⊢ φ → 1 ≠ A
42 subeq0 ⊢ 1 ∈ ℂ ∧ A ∈ ℂ → 1 − A = 0 ↔ 1 = A
43 7 1 42 sylancr ⊢ φ → 1 − A = 0 ↔ 1 = A
44 43 necon3bid ⊢ φ → 1 − A ≠ 0 ↔ 1 ≠ A
45 41 44 mpbird ⊢ φ → 1 − A ≠ 0
46 39 40 9 45 divmul3d ⊢ φ → A M − A N 1 − A = ∑ k ∈ M ..^ N A k ↔ A M − A N = ∑ k ∈ M ..^ N A k ⁢ 1 − A
47 34 46 mpbird ⊢ φ → A M − A N 1 − A = ∑ k ∈ M ..^ N A k
48 47 eqcomd ⊢ φ → ∑ k ∈ M ..^ N A k = A M − A N 1 − A