Metamath Proof Explorer


Theorem iblioosinexp

Description: sin^n on an open integral is integrable. (Contributed by Glauco Siliprandi, 29-Jun-2017)

Ref Expression
Assertion iblioosinexp ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ N ∈ ℕ 0 → x ∈ A B ⟼ sin ⁡ x N ∈ 𝐿 1

Proof

Step Hyp Ref Expression
1 ioossicc ⊢ A B ⊆ A B
2 1 a1i ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ N ∈ ℕ 0 → A B ⊆ A B
3 ioombl ⊢ A B ∈ dom ⁡ vol
4 3 a1i ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ N ∈ ℕ 0 → A B ∈ dom ⁡ vol
5 iccssre ⊢ A ∈ ℝ ∧ B ∈ ℝ → A B ⊆ ℝ
6 ax-resscn ⊢ ℝ ⊆ ℂ
7 5 6 sstrdi ⊢ A ∈ ℝ ∧ B ∈ ℝ → A B ⊆ ℂ
8 7 sselda ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ x ∈ A B → x ∈ ℂ
9 8 3adantl3 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ N ∈ ℕ 0 ∧ x ∈ A B → x ∈ ℂ
10 9 sincld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ N ∈ ℕ 0 ∧ x ∈ A B → sin ⁡ x ∈ ℂ
11 simpl3 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ N ∈ ℕ 0 ∧ x ∈ A B → N ∈ ℕ 0
12 10 11 expcld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ N ∈ ℕ 0 ∧ x ∈ A B → sin ⁡ x N ∈ ℂ
13 ibliccsinexp ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ N ∈ ℕ 0 → x ∈ A B ⟼ sin ⁡ x N ∈ 𝐿 1
14 2 4 12 13 iblss ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ N ∈ ℕ 0 → x ∈ A B ⟼ sin ⁡ x N ∈ 𝐿 1