Metamath Proof Explorer


Theorem iirev

Description: Reverse the unit interval. (Contributed by Jeff Madsen, 2-Sep-2009)

Ref Expression
Assertion iirev ⊢ X ∈ 0 1 → 1 − X ∈ 0 1

Proof

Step Hyp Ref Expression
1 1re ⊢ 1 ∈ ℝ
2 resubcl ⊢ 1 ∈ ℝ ∧ X ∈ ℝ → 1 − X ∈ ℝ
3 1 2 mpan ⊢ X ∈ ℝ → 1 − X ∈ ℝ
4 3 3ad2ant1 ⊢ X ∈ ℝ ∧ 0 ≤ X ∧ X ≤ 1 → 1 − X ∈ ℝ
5 simp3 ⊢ X ∈ ℝ ∧ 0 ≤ X ∧ X ≤ 1 → X ≤ 1
6 simp1 ⊢ X ∈ ℝ ∧ 0 ≤ X ∧ X ≤ 1 → X ∈ ℝ
7 subge0 ⊢ 1 ∈ ℝ ∧ X ∈ ℝ → 0 ≤ 1 − X ↔ X ≤ 1
8 1 6 7 sylancr ⊢ X ∈ ℝ ∧ 0 ≤ X ∧ X ≤ 1 → 0 ≤ 1 − X ↔ X ≤ 1
9 5 8 mpbird ⊢ X ∈ ℝ ∧ 0 ≤ X ∧ X ≤ 1 → 0 ≤ 1 − X
10 simp2 ⊢ X ∈ ℝ ∧ 0 ≤ X ∧ X ≤ 1 → 0 ≤ X
11 subge02 ⊢ 1 ∈ ℝ ∧ X ∈ ℝ → 0 ≤ X ↔ 1 − X ≤ 1
12 1 6 11 sylancr ⊢ X ∈ ℝ ∧ 0 ≤ X ∧ X ≤ 1 → 0 ≤ X ↔ 1 − X ≤ 1
13 10 12 mpbid ⊢ X ∈ ℝ ∧ 0 ≤ X ∧ X ≤ 1 → 1 − X ≤ 1
14 4 9 13 3jca ⊢ X ∈ ℝ ∧ 0 ≤ X ∧ X ≤ 1 → 1 − X ∈ ℝ ∧ 0 ≤ 1 − X ∧ 1 − X ≤ 1
15 elicc01 ⊢ X ∈ 0 1 ↔ X ∈ ℝ ∧ 0 ≤ X ∧ X ≤ 1
16 elicc01 ⊢ 1 − X ∈ 0 1 ↔ 1 − X ∈ ℝ ∧ 0 ≤ 1 − X ∧ 1 − X ≤ 1
17 14 15 16 3imtr4i ⊢ X ∈ 0 1 → 1 − X ∈ 0 1