Metamath Proof Explorer


Theorem imasetpreimafvbijlemf

Description: Lemma for imasetpreimafvbij : the mapping H is a function into the range of function F . (Contributed by AV, 22-Mar-2024)

Ref Expression
Hypotheses fundcmpsurinj.p ⊢ P = z | ∃ x ∈ A z = F -1 F ⁡ x
fundcmpsurinj.h ⊢ H = p ∈ P ⟼ ⋃ F p
Assertion imasetpreimafvbijlemf ⊢ F Fn A → H : P ⟶ F A

Proof

Step Hyp Ref Expression
1 fundcmpsurinj.p ⊢ P = z | ∃ x ∈ A z = F -1 F ⁡ x
2 fundcmpsurinj.h ⊢ H = p ∈ P ⟼ ⋃ F p
3 1 uniimaelsetpreimafv ⊢ F Fn A ∧ p ∈ P → ⋃ F p ∈ ran ⁡ F
4 fnima ⊢ F Fn A → F A = ran ⁡ F
5 4 adantr ⊢ F Fn A ∧ p ∈ P → F A = ran ⁡ F
6 3 5 eleqtrrd ⊢ F Fn A ∧ p ∈ P → ⋃ F p ∈ F A
7 6 2 fmptd ⊢ F Fn A → H : P ⟶ F A