Metamath Proof Explorer


Theorem islring

Description: The predicate "is a local ring". (Contributed by SN, 23-Feb-2025)

Ref Expression
Hypotheses islring.b ⊢ B = Base R
islring.a ⊢ + ˙ = + R
islring.1 ⊢ 1 ˙ = 1 R
islring.u ⊢ U = Unit ⁡ R
Assertion islring ⊢ R ∈ LRing ↔ R ∈ NzRing ∧ ∀ x ∈ B ∀ y ∈ B x + ˙ y = 1 ˙ → x ∈ U ∨ y ∈ U

Proof

Step Hyp Ref Expression
1 islring.b ⊢ B = Base R
2 islring.a ⊢ + ˙ = + R
3 islring.1 ⊢ 1 ˙ = 1 R
4 islring.u ⊢ U = Unit ⁡ R
5 fveq2 ⊢ r = R → Base r = Base R
6 5 1 eqtr4di ⊢ r = R → Base r = B
7 fveq2 ⊢ r = R → + r = + R
8 7 2 eqtr4di ⊢ r = R → + r = + ˙
9 8 oveqd ⊢ r = R → x + r y = x + ˙ y
10 fveq2 ⊢ r = R → 1 r = 1 R
11 10 3 eqtr4di ⊢ r = R → 1 r = 1 ˙
12 9 11 eqeq12d ⊢ r = R → x + r y = 1 r ↔ x + ˙ y = 1 ˙
13 fveq2 ⊢ r = R → Unit ⁡ r = Unit ⁡ R
14 13 4 eqtr4di ⊢ r = R → Unit ⁡ r = U
15 14 eleq2d ⊢ r = R → x ∈ Unit ⁡ r ↔ x ∈ U
16 14 eleq2d ⊢ r = R → y ∈ Unit ⁡ r ↔ y ∈ U
17 15 16 orbi12d ⊢ r = R → x ∈ Unit ⁡ r ∨ y ∈ Unit ⁡ r ↔ x ∈ U ∨ y ∈ U
18 12 17 imbi12d ⊢ r = R → x + r y = 1 r → x ∈ Unit ⁡ r ∨ y ∈ Unit ⁡ r ↔ x + ˙ y = 1 ˙ → x ∈ U ∨ y ∈ U
19 6 18 raleqbidv ⊢ r = R → ∀ y ∈ Base r x + r y = 1 r → x ∈ Unit ⁡ r ∨ y ∈ Unit ⁡ r ↔ ∀ y ∈ B x + ˙ y = 1 ˙ → x ∈ U ∨ y ∈ U
20 6 19 raleqbidv ⊢ r = R → ∀ x ∈ Base r ∀ y ∈ Base r x + r y = 1 r → x ∈ Unit ⁡ r ∨ y ∈ Unit ⁡ r ↔ ∀ x ∈ B ∀ y ∈ B x + ˙ y = 1 ˙ → x ∈ U ∨ y ∈ U
21 df-lring ⊢ LRing = r ∈ NzRing | ∀ x ∈ Base r ∀ y ∈ Base r x + r y = 1 r → x ∈ Unit ⁡ r ∨ y ∈ Unit ⁡ r
22 20 21 elrab2 ⊢ R ∈ LRing ↔ R ∈ NzRing ∧ ∀ x ∈ B ∀ y ∈ B x + ˙ y = 1 ˙ → x ∈ U ∨ y ∈ U