Metamath Proof Explorer


Theorem isnsqf

Description: Two ways to say that a number is not squarefree. (Contributed by Mario Carneiro, 3-Oct-2014)

Ref Expression
Assertion isnsqf ⊢ A ∈ ℕ → μ ⁡ A = 0 ↔ ∃ p ∈ ℙ p 2 ∥ A

Proof

Step Hyp Ref Expression
1 neg1cn ⊢ − 1 ∈ ℂ
2 neg1ne0 ⊢ − 1 ≠ 0
3 prmdvdsfi ⊢ A ∈ ℕ → p ∈ ℙ | p ∥ A ∈ Fin
4 hashcl ⊢ p ∈ ℙ | p ∥ A ∈ Fin → p ∈ ℙ | p ∥ A ∈ ℕ 0
5 3 4 syl ⊢ A ∈ ℕ → p ∈ ℙ | p ∥ A ∈ ℕ 0
6 5 nn0zd ⊢ A ∈ ℕ → p ∈ ℙ | p ∥ A ∈ ℤ
7 expne0i ⊢ − 1 ∈ ℂ ∧ − 1 ≠ 0 ∧ p ∈ ℙ | p ∥ A ∈ ℤ → − 1 p ∈ ℙ | p ∥ A ≠ 0
8 1 2 6 7 mp3an12i ⊢ A ∈ ℕ → − 1 p ∈ ℙ | p ∥ A ≠ 0
9 iffalse ⊢ ¬ ∃ p ∈ ℙ p 2 ∥ A → if ∃ p ∈ ℙ p 2 ∥ A 0 − 1 p ∈ ℙ | p ∥ A = − 1 p ∈ ℙ | p ∥ A
10 9 neeq1d ⊢ ¬ ∃ p ∈ ℙ p 2 ∥ A → if ∃ p ∈ ℙ p 2 ∥ A 0 − 1 p ∈ ℙ | p ∥ A ≠ 0 ↔ − 1 p ∈ ℙ | p ∥ A ≠ 0
11 8 10 syl5ibrcom ⊢ A ∈ ℕ → ¬ ∃ p ∈ ℙ p 2 ∥ A → if ∃ p ∈ ℙ p 2 ∥ A 0 − 1 p ∈ ℙ | p ∥ A ≠ 0
12 muval ⊢ A ∈ ℕ → μ ⁡ A = if ∃ p ∈ ℙ p 2 ∥ A 0 − 1 p ∈ ℙ | p ∥ A
13 12 neeq1d ⊢ A ∈ ℕ → μ ⁡ A ≠ 0 ↔ if ∃ p ∈ ℙ p 2 ∥ A 0 − 1 p ∈ ℙ | p ∥ A ≠ 0
14 11 13 sylibrd ⊢ A ∈ ℕ → ¬ ∃ p ∈ ℙ p 2 ∥ A → μ ⁡ A ≠ 0
15 14 necon4bd ⊢ A ∈ ℕ → μ ⁡ A = 0 → ∃ p ∈ ℙ p 2 ∥ A
16 iftrue ⊢ ∃ p ∈ ℙ p 2 ∥ A → if ∃ p ∈ ℙ p 2 ∥ A 0 − 1 p ∈ ℙ | p ∥ A = 0
17 12 eqeq1d ⊢ A ∈ ℕ → μ ⁡ A = 0 ↔ if ∃ p ∈ ℙ p 2 ∥ A 0 − 1 p ∈ ℙ | p ∥ A = 0
18 16 17 imbitrrid ⊢ A ∈ ℕ → ∃ p ∈ ℙ p 2 ∥ A → μ ⁡ A = 0
19 15 18 impbid ⊢ A ∈ ℕ → μ ⁡ A = 0 ↔ ∃ p ∈ ℙ p 2 ∥ A