Metamath Proof Explorer


Theorem itgeq12dv

Description: Equality theorem for an integral. (Contributed by Thierry Arnoux, 14-Feb-2017)

Ref Expression
Hypotheses itgeq12dv.2 ⊢ φ → A = B
itgeq12dv.1 ⊢ φ ∧ x ∈ A → C = D
Assertion itgeq12dv ⊢ φ → ∫ A C dx = ∫ B D dx

Proof

Step Hyp Ref Expression
1 itgeq12dv.2 ⊢ φ → A = B
2 itgeq12dv.1 ⊢ φ ∧ x ∈ A → C = D
3 2 fvoveq1d ⊢ φ ∧ x ∈ A → ℜ ⁡ C i k = ℜ ⁡ D i k
4 3 breq2d ⊢ φ ∧ x ∈ A → 0 ≤ ℜ ⁡ C i k ↔ 0 ≤ ℜ ⁡ D i k
5 4 pm5.32da ⊢ φ → x ∈ A ∧ 0 ≤ ℜ ⁡ C i k ↔ x ∈ A ∧ 0 ≤ ℜ ⁡ D i k
6 1 eleq2d ⊢ φ → x ∈ A ↔ x ∈ B
7 6 anbi1d ⊢ φ → x ∈ A ∧ 0 ≤ ℜ ⁡ D i k ↔ x ∈ B ∧ 0 ≤ ℜ ⁡ D i k
8 5 7 bitrd ⊢ φ → x ∈ A ∧ 0 ≤ ℜ ⁡ C i k ↔ x ∈ B ∧ 0 ≤ ℜ ⁡ D i k
9 3 adantrr ⊢ φ ∧ x ∈ A ∧ 0 ≤ ℜ ⁡ C i k → ℜ ⁡ C i k = ℜ ⁡ D i k
10 eqidd ⊢ φ ∧ ¬ x ∈ A ∧ 0 ≤ ℜ ⁡ C i k → 0 = 0
11 8 9 10 ifbieq12d2 ⊢ φ → if x ∈ A ∧ 0 ≤ ℜ ⁡ C i k ℜ ⁡ C i k 0 = if x ∈ B ∧ 0 ≤ ℜ ⁡ D i k ℜ ⁡ D i k 0
12 11 mpteq2dv ⊢ φ → x ∈ ℝ ⟼ if x ∈ A ∧ 0 ≤ ℜ ⁡ C i k ℜ ⁡ C i k 0 = x ∈ ℝ ⟼ if x ∈ B ∧ 0 ≤ ℜ ⁡ D i k ℜ ⁡ D i k 0
13 12 fveq2d ⊢ φ → ∫ 2 ⁡ x ∈ ℝ ⟼ if x ∈ A ∧ 0 ≤ ℜ ⁡ C i k ℜ ⁡ C i k 0 = ∫ 2 ⁡ x ∈ ℝ ⟼ if x ∈ B ∧ 0 ≤ ℜ ⁡ D i k ℜ ⁡ D i k 0
14 13 oveq2d ⊢ φ → i k ⁢ ∫ 2 ⁡ x ∈ ℝ ⟼ if x ∈ A ∧ 0 ≤ ℜ ⁡ C i k ℜ ⁡ C i k 0 = i k ⁢ ∫ 2 ⁡ x ∈ ℝ ⟼ if x ∈ B ∧ 0 ≤ ℜ ⁡ D i k ℜ ⁡ D i k 0
15 14 sumeq2sdv ⊢ φ → ∑ k = 0 3 i k ⁢ ∫ 2 ⁡ x ∈ ℝ ⟼ if x ∈ A ∧ 0 ≤ ℜ ⁡ C i k ℜ ⁡ C i k 0 = ∑ k = 0 3 i k ⁢ ∫ 2 ⁡ x ∈ ℝ ⟼ if x ∈ B ∧ 0 ≤ ℜ ⁡ D i k ℜ ⁡ D i k 0
16 eqid ⊢ ℜ ⁡ C i k = ℜ ⁡ C i k
17 16 dfitg ⊢ ∫ A C dx = ∑ k = 0 3 i k ⁢ ∫ 2 ⁡ x ∈ ℝ ⟼ if x ∈ A ∧ 0 ≤ ℜ ⁡ C i k ℜ ⁡ C i k 0
18 eqid ⊢ ℜ ⁡ D i k = ℜ ⁡ D i k
19 18 dfitg ⊢ ∫ B D dx = ∑ k = 0 3 i k ⁢ ∫ 2 ⁡ x ∈ ℝ ⟼ if x ∈ B ∧ 0 ≤ ℜ ⁡ D i k ℜ ⁡ D i k 0
20 15 17 19 3eqtr4g ⊢ φ → ∫ A C dx = ∫ B D dx