Theorem lcfrlem28

Description: Lemma for lcfr . TODO: This can be a hypothesis since the zero version of ( JY )I needs it. (Contributed by NM, 9-Mar-2015)

	Ref	Expression
Hypotheses	lcfrlem17.h	$$⊢H=\mathrm{LHyp}\left(K\right)$$
	lcfrlem17.o	$$⊢\underset{\dot{}}{\perp }=\mathrm{ocH}\left(K\right)\left(W\right)$$
	lcfrlem17.u	$$⊢U=\mathrm{DVecH}\left(K\right)\left(W\right)$$
	lcfrlem17.v	$$⊢V={\mathrm{Base}}_U$$
	lcfrlem17.p	$$⊢\underset{\dot{}}{+}={+}_U$$
	lcfrlem17.z	$$⊢\underset{\dot{}}{0}=0_U$$
	lcfrlem17.n	$$⊢N=\mathrm{LSpan}\left(U\right)$$
	lcfrlem17.a	$$⊢A=\mathrm{LSAtoms}\left(U\right)$$
	lcfrlem17.k	$$⊢\phi \to \left(K\in \mathrm{HL}\wedge W\in H\right)$$
	lcfrlem17.x	$$⊢\phi \to X\in \left(V\setminus \left\{\underset{\dot{}}{0}\right\}\right)$$
	lcfrlem17.y	$$⊢\phi \to Y\in \left(V\setminus \left\{\underset{\dot{}}{0}\right\}\right)$$
	lcfrlem17.ne	$$⊢\phi \to N\left(\left\{X\right\}\right)\ne N\left(\left\{Y\right\}\right)$$
	lcfrlem22.b	$$⊢B=N\left(\left\{X,Y\right\}\right)\cap \underset{\dot{}}{\perp }\left(\left\{X\underset{\dot{}}{+}Y\right\}\right)$$
	lcfrlem24.t	$$⊢\underset{\dot{}}{·}={\cdot }_U$$
	lcfrlem24.s	$$⊢S=\mathrm{Scalar}\left(U\right)$$
	lcfrlem24.q	$$⊢Q=0_S$$
	lcfrlem24.r	$$⊢R={\mathrm{Base}}_S$$
	lcfrlem24.j	$$⊢J=\left(x\in \left(V\setminus \left\{\underset{\dot{}}{0}\right\}\right)⟼\left(v\in V⟼\left(\iota k\in R|\exists w\in \underset{\dot{}}{\perp }\left(\left\{x\right\}\right)v=w\underset{\dot{}}{+}\left(k\underset{\dot{}}{·}x\right)\right)\right)\right)$$
	lcfrlem24.ib	$$⊢\phi \to I\in B$$
	lcfrlem24.l	$$⊢L=\mathrm{LKer}\left(U\right)$$
	lcfrlem25.d	$$⊢D=\mathrm{LDual}\left(U\right)$$
	lcfrlem28.jn	$$⊢\phi \to J\left(Y\right)\left(I\right)\ne Q$$
Assertion	lcfrlem28	$$⊢\phi \to I\ne \underset{\dot{}}{0}$$

Proof

Step	Hyp	Ref	Expression
1		lcfrlem17.h	$$⊢H=\mathrm{LHyp}\left(K\right)$$
2		lcfrlem17.o	$$⊢\underset{\dot{}}{\perp }=\mathrm{ocH}\left(K\right)\left(W\right)$$
3		lcfrlem17.u	$$⊢U=\mathrm{DVecH}\left(K\right)\left(W\right)$$
4		lcfrlem17.v	$$⊢V={\mathrm{Base}}_U$$
5		lcfrlem17.p	$$⊢\underset{\dot{}}{+}={+}_U$$
6		lcfrlem17.z	$$⊢\underset{\dot{}}{0}=0_U$$
7		lcfrlem17.n	$$⊢N=\mathrm{LSpan}\left(U\right)$$
8		lcfrlem17.a	$$⊢A=\mathrm{LSAtoms}\left(U\right)$$
9		lcfrlem17.k	$$⊢\phi \to \left(K\in \mathrm{HL}\wedge W\in H\right)$$
10		lcfrlem17.x	$$⊢\phi \to X\in \left(V\setminus \left\{\underset{\dot{}}{0}\right\}\right)$$
11		lcfrlem17.y	$$⊢\phi \to Y\in \left(V\setminus \left\{\underset{\dot{}}{0}\right\}\right)$$
12		lcfrlem17.ne	$$⊢\phi \to N\left(\left\{X\right\}\right)\ne N\left(\left\{Y\right\}\right)$$
13		lcfrlem22.b	$$⊢B=N\left(\left\{X,Y\right\}\right)\cap \underset{\dot{}}{\perp }\left(\left\{X\underset{\dot{}}{+}Y\right\}\right)$$
14		lcfrlem24.t	$$⊢\underset{\dot{}}{·}={\cdot }_U$$
15		lcfrlem24.s	$$⊢S=\mathrm{Scalar}\left(U\right)$$
16		lcfrlem24.q	$$⊢Q=0_S$$
17		lcfrlem24.r	$$⊢R={\mathrm{Base}}_S$$
18		lcfrlem24.j	$$⊢J=\left(x\in \left(V\setminus \left\{\underset{\dot{}}{0}\right\}\right)⟼\left(v\in V⟼\left(\iota k\in R|\exists w\in \underset{\dot{}}{\perp }\left(\left\{x\right\}\right)v=w\underset{\dot{}}{+}\left(k\underset{\dot{}}{·}x\right)\right)\right)\right)$$
19		lcfrlem24.ib	$$⊢\phi \to I\in B$$
20		lcfrlem24.l	$$⊢L=\mathrm{LKer}\left(U\right)$$
21		lcfrlem25.d	$$⊢D=\mathrm{LDual}\left(U\right)$$
22		lcfrlem28.jn	$$⊢\phi \to J\left(Y\right)\left(I\right)\ne Q$$
23	1 3 9	dvhlmod	$$⊢\phi \to U\in \mathrm{LMod}$$
24		eqid	$$⊢\mathrm{LFnl}\left(U\right)=\mathrm{LFnl}\left(U\right)$$
25		eqid	$$⊢0_D=0_D$$
26		eqid	$$⊢\left\{f\in \mathrm{LFnl}\left(U\right)|\underset{\dot{}}{\perp }\left(\underset{\dot{}}{\perp }\left(L\left(f\right)\right)\right)=L\left(f\right)\right\}=\left\{f\in \mathrm{LFnl}\left(U\right)|\underset{\dot{}}{\perp }\left(\underset{\dot{}}{\perp }\left(L\left(f\right)\right)\right)=L\left(f\right)\right\}$$
27	1 2 3 4 5 14 15 17 6 24 20 21 25 26 18 9 11	lcfrlem10	$$⊢\phi \to J\left(Y\right)\in \mathrm{LFnl}\left(U\right)$$
28	15 16 6 24	lfl0	$$⊢\left(U\in \mathrm{LMod}\wedge J\left(Y\right)\in \mathrm{LFnl}\left(U\right)\right)\to J\left(Y\right)\left(\underset{\dot{}}{0}\right)=Q$$
29	23 27 28	syl2anc	$$⊢\phi \to J\left(Y\right)\left(\underset{\dot{}}{0}\right)=Q$$
30		fveqeq2	$$⊢I=\underset{\dot{}}{0}\to \left(J\left(Y\right)\left(I\right)=Q\leftrightarrow J\left(Y\right)\left(\underset{\dot{}}{0}\right)=Q\right)$$
31	29 30	syl5ibrcom	$$⊢\phi \to \left(I=\underset{\dot{}}{0}\to J\left(Y\right)\left(I\right)=Q\right)$$
32	31	necon3d	$$⊢\phi \to \left(J\left(Y\right)\left(I\right)\ne Q\to I\ne \underset{\dot{}}{0}\right)$$
33	22 32	mpd	$$⊢\phi \to I\ne \underset{\dot{}}{0}$$