Metamath Proof Explorer


Theorem ldualvsval

Description: Value of scalar product operation value for the dual of a vector space. (Contributed by NM, 18-Oct-2014)

Ref Expression
Hypotheses ldualfvs.f ⊢ F = LFnl ⁡ W
ldualfvs.v ⊢ V = Base W
ldualfvs.r ⊢ R = Scalar ⁡ W
ldualfvs.k ⊢ K = Base R
ldualfvs.t ⊢ × ˙ = ⋅ R
ldualfvs.d ⊢ D = LDual ⁡ W
ldualfvs.s ⊢ ∙ ˙ = ⋅ D
ldualfvs.w ⊢ φ → W ∈ Y
ldualvs.x ⊢ φ → X ∈ K
ldualvs.g ⊢ φ → G ∈ F
ldualvs.a ⊢ φ → A ∈ V
Assertion ldualvsval ⊢ φ → X ∙ ˙ G ⁡ A = G ⁡ A × ˙ X

Proof

Step Hyp Ref Expression
1 ldualfvs.f ⊢ F = LFnl ⁡ W
2 ldualfvs.v ⊢ V = Base W
3 ldualfvs.r ⊢ R = Scalar ⁡ W
4 ldualfvs.k ⊢ K = Base R
5 ldualfvs.t ⊢ × ˙ = ⋅ R
6 ldualfvs.d ⊢ D = LDual ⁡ W
7 ldualfvs.s ⊢ ∙ ˙ = ⋅ D
8 ldualfvs.w ⊢ φ → W ∈ Y
9 ldualvs.x ⊢ φ → X ∈ K
10 ldualvs.g ⊢ φ → G ∈ F
11 ldualvs.a ⊢ φ → A ∈ V
12 1 2 3 4 5 6 7 8 9 10 ldualvs ⊢ φ → X ∙ ˙ G = G × ˙ f V × X
13 12 fveq1d ⊢ φ → X ∙ ˙ G ⁡ A = G × ˙ f V × X ⁡ A
14 2 fvexi ⊢ V ∈ V
15 14 a1i ⊢ φ → V ∈ V
16 3 4 2 1 lflf ⊢ W ∈ Y ∧ G ∈ F → G : V ⟶ K
17 8 10 16 syl2anc ⊢ φ → G : V ⟶ K
18 17 ffnd ⊢ φ → G Fn V
19 eqidd ⊢ φ ∧ A ∈ V → G ⁡ A = G ⁡ A
20 15 9 18 19 ofc2 ⊢ φ ∧ A ∈ V → G × ˙ f V × X ⁡ A = G ⁡ A × ˙ X
21 11 20 mpdan ⊢ φ → G × ˙ f V × X ⁡ A = G ⁡ A × ˙ X
22 13 21 eqtrd ⊢ φ → X ∙ ˙ G ⁡ A = G ⁡ A × ˙ X