Metamath Proof Explorer


Theorem lplnn0N

Description: A lattice plane is nonzero. (Contributed by NM, 15-Jul-2012) (New usage is discouraged.)

Ref Expression
Hypotheses lplnn0.z ⊢ 0 ˙ = 0. ⁡ K
lplnn0.p ⊢ P = LPlanes ⁡ K
Assertion lplnn0N ⊢ K ∈ HL ∧ X ∈ P → X ≠ 0 ˙

Proof

Step Hyp Ref Expression
1 lplnn0.z ⊢ 0 ˙ = 0. ⁡ K
2 lplnn0.p ⊢ P = LPlanes ⁡ K
3 eqid ⊢ Atoms ⁡ K = Atoms ⁡ K
4 3 atex ⊢ K ∈ HL → Atoms ⁡ K ≠ ∅
5 n0 ⊢ Atoms ⁡ K ≠ ∅ ↔ ∃ p p ∈ Atoms ⁡ K
6 4 5 sylib ⊢ K ∈ HL → ∃ p p ∈ Atoms ⁡ K
7 6 adantr ⊢ K ∈ HL ∧ X ∈ P → ∃ p p ∈ Atoms ⁡ K
8 eqid ⊢ ≤ K = ≤ K
9 8 3 2 lplnnleat ⊢ K ∈ HL ∧ X ∈ P ∧ p ∈ Atoms ⁡ K → ¬ X ≤ K p
10 9 3expa ⊢ K ∈ HL ∧ X ∈ P ∧ p ∈ Atoms ⁡ K → ¬ X ≤ K p
11 hlop ⊢ K ∈ HL → K ∈ OP
12 11 ad2antrr ⊢ K ∈ HL ∧ X ∈ P ∧ p ∈ Atoms ⁡ K → K ∈ OP
13 eqid ⊢ Base K = Base K
14 13 3 atbase ⊢ p ∈ Atoms ⁡ K → p ∈ Base K
15 14 adantl ⊢ K ∈ HL ∧ X ∈ P ∧ p ∈ Atoms ⁡ K → p ∈ Base K
16 13 8 1 op0le ⊢ K ∈ OP ∧ p ∈ Base K → 0 ˙ ≤ K p
17 12 15 16 syl2anc ⊢ K ∈ HL ∧ X ∈ P ∧ p ∈ Atoms ⁡ K → 0 ˙ ≤ K p
18 breq1 ⊢ X = 0 ˙ → X ≤ K p ↔ 0 ˙ ≤ K p
19 17 18 syl5ibrcom ⊢ K ∈ HL ∧ X ∈ P ∧ p ∈ Atoms ⁡ K → X = 0 ˙ → X ≤ K p
20 19 necon3bd ⊢ K ∈ HL ∧ X ∈ P ∧ p ∈ Atoms ⁡ K → ¬ X ≤ K p → X ≠ 0 ˙
21 10 20 mpd ⊢ K ∈ HL ∧ X ∈ P ∧ p ∈ Atoms ⁡ K → X ≠ 0 ˙
22 7 21 exlimddv ⊢ K ∈ HL ∧ X ∈ P → X ≠ 0 ˙