Metamath Proof Explorer


Theorem lshpat

Description: Create an atom under a hyperplane. Part of proof of Lemma B in Crawley p. 112. ( lhpat analog.) TODO: This changes U C V in l1cvpat and l1cvat to U e. H , which in turn change U e. H in islshpcv to U C V , with a couple of conversions of span to atom. Seems convoluted. Would a direct proof be better? (Contributed by NM, 11-Jan-2015)

Ref Expression
Hypotheses lshpat.s ⊢ S = LSubSp ⁡ W
lshpat.p ⊢ ⊕ ˙ = LSSum ⁡ W
ishpat.h ⊢ H = LSHyp ⁡ W
lshpat.a ⊢ A = LSAtoms ⁡ W
lshpat.w ⊢ φ → W ∈ LVec
lshpat.l ⊢ φ → U ∈ H
lshpat.q ⊢ φ → Q ∈ A
lshpat.r ⊢ φ → R ∈ A
lshpat.n ⊢ φ → Q ≠ R
lshpat.m ⊢ φ → ¬ Q ⊆ U
Assertion lshpat ⊢ φ → Q ⊕ ˙ R ∩ U ∈ A

Proof

Step Hyp Ref Expression
1 lshpat.s ⊢ S = LSubSp ⁡ W
2 lshpat.p ⊢ ⊕ ˙ = LSSum ⁡ W
3 ishpat.h ⊢ H = LSHyp ⁡ W
4 lshpat.a ⊢ A = LSAtoms ⁡ W
5 lshpat.w ⊢ φ → W ∈ LVec
6 lshpat.l ⊢ φ → U ∈ H
7 lshpat.q ⊢ φ → Q ∈ A
8 lshpat.r ⊢ φ → R ∈ A
9 lshpat.n ⊢ φ → Q ≠ R
10 lshpat.m ⊢ φ → ¬ Q ⊆ U
11 eqid ⊢ Base W = Base W
12 eqid ⊢ ⋖ L ⁡ W = ⋖ L ⁡ W
13 11 1 3 12 5 islshpcv ⊢ φ → U ∈ H ↔ U ∈ S ∧ U ⋖ L ⁡ W Base W
14 6 13 mpbid ⊢ φ → U ∈ S ∧ U ⋖ L ⁡ W Base W
15 14 simpld ⊢ φ → U ∈ S
16 14 simprd ⊢ φ → U ⋖ L ⁡ W Base W
17 11 1 2 4 12 5 15 7 8 9 16 10 l1cvat ⊢ φ → Q ⊕ ˙ R ∩ U ∈ A