Metamath Proof Explorer


Theorem lssincl

Description: The intersection of two subspaces is a subspace. (Contributed by NM, 7-Mar-2014) (Revised by Mario Carneiro, 19-Jun-2014)

Ref Expression
Hypothesis lssintcl.s ⊢ S = LSubSp ⁡ W
Assertion lssincl ⊢ W ∈ LMod ∧ T ∈ S ∧ U ∈ S → T ∩ U ∈ S

Proof

Step Hyp Ref Expression
1 lssintcl.s ⊢ S = LSubSp ⁡ W
2 intprg ⊢ T ∈ S ∧ U ∈ S → ⋂ T U = T ∩ U
3 2 3adant1 ⊢ W ∈ LMod ∧ T ∈ S ∧ U ∈ S → ⋂ T U = T ∩ U
4 simp1 ⊢ W ∈ LMod ∧ T ∈ S ∧ U ∈ S → W ∈ LMod
5 prssi ⊢ T ∈ S ∧ U ∈ S → T U ⊆ S
6 5 3adant1 ⊢ W ∈ LMod ∧ T ∈ S ∧ U ∈ S → T U ⊆ S
7 prnzg ⊢ T ∈ S → T U ≠ ∅
8 7 3ad2ant2 ⊢ W ∈ LMod ∧ T ∈ S ∧ U ∈ S → T U ≠ ∅
9 1 lssintcl ⊢ W ∈ LMod ∧ T U ⊆ S ∧ T U ≠ ∅ → ⋂ T U ∈ S
10 4 6 8 9 syl3anc ⊢ W ∈ LMod ∧ T ∈ S ∧ U ∈ S → ⋂ T U ∈ S
11 3 10 eqeltrrd ⊢ W ∈ LMod ∧ T ∈ S ∧ U ∈ S → T ∩ U ∈ S