Metamath Proof Explorer


Theorem mo5f

Description: Alternate definition of "at most one." (Contributed by Thierry Arnoux, 1-Mar-2017)

Ref Expression
Hypotheses mo5f.1 ⊢ Ⅎ i φ
mo5f.2 ⊢ Ⅎ j φ
Assertion mo5f ⊢ ∃* x φ ↔ ∀ i ∀ j i x φ ∧ j x φ → i = j

Proof

Step Hyp Ref Expression
1 mo5f.1 ⊢ Ⅎ i φ
2 mo5f.2 ⊢ Ⅎ j φ
3 2 mo3 ⊢ ∃* x φ ↔ ∀ x ∀ j φ ∧ j x φ → x = j
4 1 nfsbv ⊢ Ⅎ i j x φ
5 1 4 nfan ⊢ Ⅎ i φ ∧ j x φ
6 nfv ⊢ Ⅎ i x = j
7 5 6 nfim ⊢ Ⅎ i φ ∧ j x φ → x = j
8 7 nfal ⊢ Ⅎ i ∀ j φ ∧ j x φ → x = j
9 8 sb8f ⊢ ∀ x ∀ j φ ∧ j x φ → x = j ↔ ∀ i i x ∀ j φ ∧ j x φ → x = j
10 sbim ⊢ i x φ ∧ j x φ → x = j ↔ i x φ ∧ j x φ → i x x = j
11 sban ⊢ i x φ ∧ j x φ ↔ i x φ ∧ i x j x φ
12 nfs1v ⊢ Ⅎ x j x φ
13 12 sbf ⊢ i x j x φ ↔ j x φ
14 13 bicomi ⊢ j x φ ↔ i x j x φ
15 14 anbi2i ⊢ i x φ ∧ j x φ ↔ i x φ ∧ i x j x φ
16 11 15 bitr4i ⊢ i x φ ∧ j x φ ↔ i x φ ∧ j x φ
17 equsb3 ⊢ i x x = j ↔ i = j
18 16 17 imbi12i ⊢ i x φ ∧ j x φ → i x x = j ↔ i x φ ∧ j x φ → i = j
19 10 18 bitri ⊢ i x φ ∧ j x φ → x = j ↔ i x φ ∧ j x φ → i = j
20 19 sbalv ⊢ i x ∀ j φ ∧ j x φ → x = j ↔ ∀ j i x φ ∧ j x φ → i = j
21 20 albii ⊢ ∀ i i x ∀ j φ ∧ j x φ → x = j ↔ ∀ i ∀ j i x φ ∧ j x φ → i = j
22 3 9 21 3bitri ⊢ ∃* x φ ↔ ∀ i ∀ j i x φ ∧ j x φ → i = j