Metamath Proof Explorer


Theorem nmtri2

Description: Triangle inequality for the norm of two subtractions. (Contributed by NM, 24-Feb-2008) (Revised by AV, 8-Oct-2021)

Ref Expression
Hypotheses nmtri2.x ⊢ X = Base G
nmtri2.n ⊢ N = norm ⁡ G
nmtri2.m ⊢ - ˙ = - G
Assertion nmtri2 ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X ∧ C ∈ X → N ⁡ A - ˙ C ≤ N ⁡ A - ˙ B + N ⁡ B - ˙ C

Proof

Step Hyp Ref Expression
1 nmtri2.x ⊢ X = Base G
2 nmtri2.n ⊢ N = norm ⁡ G
3 nmtri2.m ⊢ - ˙ = - G
4 ngpgrp ⊢ G ∈ NrmGrp → G ∈ Grp
5 eqid ⊢ + G = + G
6 1 5 3 grpnpncan ⊢ G ∈ Grp ∧ A ∈ X ∧ B ∈ X ∧ C ∈ X → A - ˙ B + G B - ˙ C = A - ˙ C
7 6 eqcomd ⊢ G ∈ Grp ∧ A ∈ X ∧ B ∈ X ∧ C ∈ X → A - ˙ C = A - ˙ B + G B - ˙ C
8 4 7 sylan ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X ∧ C ∈ X → A - ˙ C = A - ˙ B + G B - ˙ C
9 8 fveq2d ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X ∧ C ∈ X → N ⁡ A - ˙ C = N ⁡ A - ˙ B + G B - ˙ C
10 simpl ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X ∧ C ∈ X → G ∈ NrmGrp
11 4 adantr ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X ∧ C ∈ X → G ∈ Grp
12 simpr1 ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X ∧ C ∈ X → A ∈ X
13 simpr2 ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X ∧ C ∈ X → B ∈ X
14 1 3 grpsubcl ⊢ G ∈ Grp ∧ A ∈ X ∧ B ∈ X → A - ˙ B ∈ X
15 11 12 13 14 syl3anc ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X ∧ C ∈ X → A - ˙ B ∈ X
16 simpr3 ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X ∧ C ∈ X → C ∈ X
17 1 3 grpsubcl ⊢ G ∈ Grp ∧ B ∈ X ∧ C ∈ X → B - ˙ C ∈ X
18 11 13 16 17 syl3anc ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X ∧ C ∈ X → B - ˙ C ∈ X
19 1 2 5 nmtri ⊢ G ∈ NrmGrp ∧ A - ˙ B ∈ X ∧ B - ˙ C ∈ X → N ⁡ A - ˙ B + G B - ˙ C ≤ N ⁡ A - ˙ B + N ⁡ B - ˙ C
20 10 15 18 19 syl3anc ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X ∧ C ∈ X → N ⁡ A - ˙ B + G B - ˙ C ≤ N ⁡ A - ˙ B + N ⁡ B - ˙ C
21 9 20 eqbrtrd ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X ∧ C ∈ X → N ⁡ A - ˙ C ≤ N ⁡ A - ˙ B + N ⁡ B - ˙ C