Metamath Proof Explorer


Theorem nn0diffz0

Description: Upper set of the nonnegative integers. (Contributed by Thierry Arnoux, 25-Jan-2026)

Ref Expression
Assertion nn0diffz0 ⊢ N ∈ ℕ 0 → ℕ 0 ∖ 0 … N = ℤ ≥ N + 1

Proof

Step Hyp Ref Expression
1 nn0uz ⊢ ℕ 0 = ℤ ≥ 0
2 peano2nn0 ⊢ N ∈ ℕ 0 → N + 1 ∈ ℕ 0
3 2 1 eleqtrdi ⊢ N ∈ ℕ 0 → N + 1 ∈ ℤ ≥ 0
4 fzouzsplit ⊢ N + 1 ∈ ℤ ≥ 0 → ℤ ≥ 0 = 0 ..^ N + 1 ∪ ℤ ≥ N + 1
5 3 4 syl ⊢ N ∈ ℕ 0 → ℤ ≥ 0 = 0 ..^ N + 1 ∪ ℤ ≥ N + 1
6 1 5 eqtrid ⊢ N ∈ ℕ 0 → ℕ 0 = 0 ..^ N + 1 ∪ ℤ ≥ N + 1
7 6 difeq1d ⊢ N ∈ ℕ 0 → ℕ 0 ∖ 0 … N = 0 ..^ N + 1 ∪ ℤ ≥ N + 1 ∖ 0 … N
8 uncom ⊢ ℤ ≥ N + 1 ∪ 0 … N = 0 … N ∪ ℤ ≥ N + 1
9 nn0z ⊢ N ∈ ℕ 0 → N ∈ ℤ
10 fzval3 ⊢ N ∈ ℤ → 0 … N = 0 ..^ N + 1
11 9 10 syl ⊢ N ∈ ℕ 0 → 0 … N = 0 ..^ N + 1
12 11 uneq1d ⊢ N ∈ ℕ 0 → 0 … N ∪ ℤ ≥ N + 1 = 0 ..^ N + 1 ∪ ℤ ≥ N + 1
13 8 12 eqtrid ⊢ N ∈ ℕ 0 → ℤ ≥ N + 1 ∪ 0 … N = 0 ..^ N + 1 ∪ ℤ ≥ N + 1
14 13 difeq1d ⊢ N ∈ ℕ 0 → ℤ ≥ N + 1 ∪ 0 … N ∖ 0 … N = 0 ..^ N + 1 ∪ ℤ ≥ N + 1 ∖ 0 … N
15 11 ineq2d ⊢ N ∈ ℕ 0 → ℤ ≥ N + 1 ∩ 0 … N = ℤ ≥ N + 1 ∩ 0 ..^ N + 1
16 fzouzdisj ⊢ 0 ..^ N + 1 ∩ ℤ ≥ N + 1 = ∅
17 16 ineqcomi ⊢ ℤ ≥ N + 1 ∩ 0 ..^ N + 1 = ∅
18 15 17 eqtrdi ⊢ N ∈ ℕ 0 → ℤ ≥ N + 1 ∩ 0 … N = ∅
19 undif5 ⊢ ℤ ≥ N + 1 ∩ 0 … N = ∅ → ℤ ≥ N + 1 ∪ 0 … N ∖ 0 … N = ℤ ≥ N + 1
20 18 19 syl ⊢ N ∈ ℕ 0 → ℤ ≥ N + 1 ∪ 0 … N ∖ 0 … N = ℤ ≥ N + 1
21 7 14 20 3eqtr2d ⊢ N ∈ ℕ 0 → ℕ 0 ∖ 0 … N = ℤ ≥ N + 1