Metamath Proof Explorer


Theorem nnasmo

Description: There is at most one left additive inverse for natural number addition. (Contributed by Scott Fenton, 17-Oct-2024)

Ref Expression
Assertion nnasmo ⊢ A ∈ ω → ∃* x ∈ ω A + 𝑜 x = B

Proof

Step Hyp Ref Expression
1 eqtr3 ⊢ A + 𝑜 x = B ∧ A + 𝑜 y = B → A + 𝑜 x = A + 𝑜 y
2 nnacan ⊢ A ∈ ω ∧ x ∈ ω ∧ y ∈ ω → A + 𝑜 x = A + 𝑜 y ↔ x = y
3 1 2 imbitrid ⊢ A ∈ ω ∧ x ∈ ω ∧ y ∈ ω → A + 𝑜 x = B ∧ A + 𝑜 y = B → x = y
4 3 3expb ⊢ A ∈ ω ∧ x ∈ ω ∧ y ∈ ω → A + 𝑜 x = B ∧ A + 𝑜 y = B → x = y
5 4 ralrimivva ⊢ A ∈ ω → ∀ x ∈ ω ∀ y ∈ ω A + 𝑜 x = B ∧ A + 𝑜 y = B → x = y
6 oveq2 ⊢ x = y → A + 𝑜 x = A + 𝑜 y
7 6 eqeq1d ⊢ x = y → A + 𝑜 x = B ↔ A + 𝑜 y = B
8 7 rmo4 ⊢ ∃* x ∈ ω A + 𝑜 x = B ↔ ∀ x ∈ ω ∀ y ∈ ω A + 𝑜 x = B ∧ A + 𝑜 y = B → x = y
9 5 8 sylibr ⊢ A ∈ ω → ∃* x ∈ ω A + 𝑜 x = B