Metamath Proof Explorer


Theorem ofcfeqd2

Description: Equality theorem for function/constant operation value. (Contributed by Thierry Arnoux, 31-Jan-2017)

Ref Expression
Hypotheses ofcfeqd2.1 ⊢ φ ∧ x ∈ A → F ⁡ x ∈ B
ofcfeqd2.2 ⊢ φ ∧ y ∈ B → y R C = y P C
ofcfeqd2.3 ⊢ φ → F Fn A
ofcfeqd2.4 ⊢ φ → A ∈ V
ofcfeqd2.5 ⊢ φ → C ∈ W
Assertion ofcfeqd2 ⊢ φ → F ∘ fc ⁡ R C = F ∘ fc ⁡ P C

Proof

Step Hyp Ref Expression
1 ofcfeqd2.1 ⊢ φ ∧ x ∈ A → F ⁡ x ∈ B
2 ofcfeqd2.2 ⊢ φ ∧ y ∈ B → y R C = y P C
3 ofcfeqd2.3 ⊢ φ → F Fn A
4 ofcfeqd2.4 ⊢ φ → A ∈ V
5 ofcfeqd2.5 ⊢ φ → C ∈ W
6 oveq1 ⊢ y = F ⁡ x → y R C = F ⁡ x R C
7 oveq1 ⊢ y = F ⁡ x → y P C = F ⁡ x P C
8 6 7 eqeq12d ⊢ y = F ⁡ x → y R C = y P C ↔ F ⁡ x R C = F ⁡ x P C
9 2 ralrimiva ⊢ φ → ∀ y ∈ B y R C = y P C
10 9 adantr ⊢ φ ∧ x ∈ A → ∀ y ∈ B y R C = y P C
11 8 10 1 rspcdva ⊢ φ ∧ x ∈ A → F ⁡ x R C = F ⁡ x P C
12 11 mpteq2dva ⊢ φ → x ∈ A ⟼ F ⁡ x R C = x ∈ A ⟼ F ⁡ x P C
13 eqidd ⊢ φ ∧ x ∈ A → F ⁡ x = F ⁡ x
14 3 4 5 13 ofcfval ⊢ φ → F ∘ fc ⁡ R C = x ∈ A ⟼ F ⁡ x R C
15 3 4 5 13 ofcfval ⊢ φ → F ∘ fc ⁡ P C = x ∈ A ⟼ F ⁡ x P C
16 12 14 15 3eqtr4d ⊢ φ → F ∘ fc ⁡ R C = F ∘ fc ⁡ P C