Metamath Proof Explorer


Theorem ofcfeqd2

Description: Equality theorem for function/constant operation value. (Contributed by Thierry Arnoux, 31-Jan-2017)

Ref Expression
Hypotheses ofcfeqd2.1 ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → ( 𝐹 ‘ 𝑥 ) ∈ 𝐵 )
ofcfeqd2.2 ⊢ ( ( 𝜑 ∧ 𝑦 ∈ 𝐵 ) → ( 𝑦 𝑅 𝐶 ) = ( 𝑦 𝑃 𝐶 ) )
ofcfeqd2.3 ⊢ ( 𝜑 → 𝐹 Fn 𝐴 )
ofcfeqd2.4 ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
ofcfeqd2.5 ⊢ ( 𝜑 → 𝐶 ∈ 𝑊 )
Assertion ofcfeqd2 ( 𝜑 → ( 𝐹 ∘f/c 𝑅 𝐶 ) = ( 𝐹 ∘f/c 𝑃 𝐶 ) )

Proof

Step Hyp Ref Expression
1 ofcfeqd2.1 ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → ( 𝐹 ‘ 𝑥 ) ∈ 𝐵 )
2 ofcfeqd2.2 ⊢ ( ( 𝜑 ∧ 𝑦 ∈ 𝐵 ) → ( 𝑦 𝑅 𝐶 ) = ( 𝑦 𝑃 𝐶 ) )
3 ofcfeqd2.3 ⊢ ( 𝜑 → 𝐹 Fn 𝐴 )
4 ofcfeqd2.4 ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
5 ofcfeqd2.5 ⊢ ( 𝜑 → 𝐶 ∈ 𝑊 )
6 oveq1 ⊢ ( 𝑦 = ( 𝐹 ‘ 𝑥 ) → ( 𝑦 𝑅 𝐶 ) = ( ( 𝐹 ‘ 𝑥 ) 𝑅 𝐶 ) )
7 oveq1 ⊢ ( 𝑦 = ( 𝐹 ‘ 𝑥 ) → ( 𝑦 𝑃 𝐶 ) = ( ( 𝐹 ‘ 𝑥 ) 𝑃 𝐶 ) )
8 6 7 eqeq12d ⊢ ( 𝑦 = ( 𝐹 ‘ 𝑥 ) → ( ( 𝑦 𝑅 𝐶 ) = ( 𝑦 𝑃 𝐶 ) ↔ ( ( 𝐹 ‘ 𝑥 ) 𝑅 𝐶 ) = ( ( 𝐹 ‘ 𝑥 ) 𝑃 𝐶 ) ) )
9 2 ralrimiva ⊢ ( 𝜑 → ∀ 𝑦 ∈ 𝐵 ( 𝑦 𝑅 𝐶 ) = ( 𝑦 𝑃 𝐶 ) )
10 9 adantr ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → ∀ 𝑦 ∈ 𝐵 ( 𝑦 𝑅 𝐶 ) = ( 𝑦 𝑃 𝐶 ) )
11 8 10 1 rspcdva ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → ( ( 𝐹 ‘ 𝑥 ) 𝑅 𝐶 ) = ( ( 𝐹 ‘ 𝑥 ) 𝑃 𝐶 ) )
12 11 mpteq2dva ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ ( ( 𝐹 ‘ 𝑥 ) 𝑅 𝐶 ) ) = ( 𝑥 ∈ 𝐴 ↦ ( ( 𝐹 ‘ 𝑥 ) 𝑃 𝐶 ) ) )
13 eqidd ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → ( 𝐹 ‘ 𝑥 ) = ( 𝐹 ‘ 𝑥 ) )
14 3 4 5 13 ofcfval ⊢ ( 𝜑 → ( 𝐹 ∘f/c 𝑅 𝐶 ) = ( 𝑥 ∈ 𝐴 ↦ ( ( 𝐹 ‘ 𝑥 ) 𝑅 𝐶 ) ) )
15 3 4 5 13 ofcfval ⊢ ( 𝜑 → ( 𝐹 ∘f/c 𝑃 𝐶 ) = ( 𝑥 ∈ 𝐴 ↦ ( ( 𝐹 ‘ 𝑥 ) 𝑃 𝐶 ) ) )
16 12 14 15 3eqtr4d ⊢ ( 𝜑 → ( 𝐹 ∘f/c 𝑅 𝐶 ) = ( 𝐹 ∘f/c 𝑃 𝐶 ) )