Metamath Proof Explorer


Theorem or2expropbilem1

Description: Lemma 1 for or2expropbi and ich2exprop . (Contributed by AV, 16-Jul-2023)

Ref Expression
Assertion or2expropbilem1 ⊢ A ∈ X ∧ B ∈ X → A = a ∧ B = b → φ → ∃ x ∃ y A B = x y ∧ [˙y / b]˙ [˙x / a]˙ φ

Proof

Step Hyp Ref Expression
1 vex ⊢ a ∈ V
2 vex ⊢ b ∈ V
3 1 2 pm3.2i ⊢ a ∈ V ∧ b ∈ V
4 3 a1i ⊢ A ∈ X ∧ B ∈ X → a ∈ V ∧ b ∈ V
5 4 anim1ci ⊢ A ∈ X ∧ B ∈ X ∧ φ → φ ∧ a ∈ V ∧ b ∈ V
6 5 adantr ⊢ A ∈ X ∧ B ∈ X ∧ φ ∧ A = a ∧ B = b → φ ∧ a ∈ V ∧ b ∈ V
7 sbcid ⊢ [˙b / b]˙ [˙a / a]˙ φ ↔ [˙a / a]˙ φ
8 sbcid ⊢ [˙a / a]˙ φ ↔ φ
9 7 8 sylbbr ⊢ φ → [˙b / b]˙ [˙a / a]˙ φ
10 9 adantl ⊢ A ∈ X ∧ B ∈ X ∧ φ → [˙b / b]˙ [˙a / a]˙ φ
11 opeq12 ⊢ A = a ∧ B = b → A B = a b
12 10 11 anim12ci ⊢ A ∈ X ∧ B ∈ X ∧ φ ∧ A = a ∧ B = b → A B = a b ∧ [˙b / b]˙ [˙a / a]˙ φ
13 nfv ⊢ Ⅎ x A B = a b ∧ [˙b / b]˙ [˙a / a]˙ φ
14 nfv ⊢ Ⅎ y A B = a b ∧ [˙b / b]˙ [˙a / a]˙ φ
15 opeq12 ⊢ x = a ∧ y = b → x y = a b
16 15 eqeq2d ⊢ x = a ∧ y = b → A B = x y ↔ A B = a b
17 dfsbcq ⊢ y = b → [˙y / b]˙ [˙x / a]˙ φ ↔ [˙b / b]˙ [˙x / a]˙ φ
18 dfsbcq ⊢ x = a → [˙x / a]˙ φ ↔ [˙a / a]˙ φ
19 18 sbcbidv ⊢ x = a → [˙b / b]˙ [˙x / a]˙ φ ↔ [˙b / b]˙ [˙a / a]˙ φ
20 17 19 sylan9bbr ⊢ x = a ∧ y = b → [˙y / b]˙ [˙x / a]˙ φ ↔ [˙b / b]˙ [˙a / a]˙ φ
21 16 20 anbi12d ⊢ x = a ∧ y = b → A B = x y ∧ [˙y / b]˙ [˙x / a]˙ φ ↔ A B = a b ∧ [˙b / b]˙ [˙a / a]˙ φ
22 21 adantl ⊢ φ ∧ x = a ∧ y = b → A B = x y ∧ [˙y / b]˙ [˙x / a]˙ φ ↔ A B = a b ∧ [˙b / b]˙ [˙a / a]˙ φ
23 13 14 22 spc2ed ⊢ φ ∧ a ∈ V ∧ b ∈ V → A B = a b ∧ [˙b / b]˙ [˙a / a]˙ φ → ∃ x ∃ y A B = x y ∧ [˙y / b]˙ [˙x / a]˙ φ
24 6 12 23 sylc ⊢ A ∈ X ∧ B ∈ X ∧ φ ∧ A = a ∧ B = b → ∃ x ∃ y A B = x y ∧ [˙y / b]˙ [˙x / a]˙ φ
25 24 exp31 ⊢ A ∈ X ∧ B ∈ X → φ → A = a ∧ B = b → ∃ x ∃ y A B = x y ∧ [˙y / b]˙ [˙x / a]˙ φ
26 25 com23 ⊢ A ∈ X ∧ B ∈ X → A = a ∧ B = b → φ → ∃ x ∃ y A B = x y ∧ [˙y / b]˙ [˙x / a]˙ φ