Metamath Proof Explorer


Theorem ordtri3or

Description: A trichotomy law for ordinals. Proposition 7.10 of TakeutiZaring p. 38. Theorem 1.9(iii) of Schloeder p. 1. (Contributed by NM, 10-May-1994) (Proof shortened by Andrew Salmon, 25-Jul-2011)

Ref Expression
Assertion ordtri3or ⊢ Ord ⁡ A ∧ Ord ⁡ B → A ∈ B ∨ A = B ∨ B ∈ A

Proof

Step Hyp Ref Expression
1 ordin ⊢ Ord ⁡ A ∧ Ord ⁡ B → Ord ⁡ A ∩ B
2 ordirr ⊢ Ord ⁡ A ∩ B → ¬ A ∩ B ∈ A ∩ B
3 1 2 syl ⊢ Ord ⁡ A ∧ Ord ⁡ B → ¬ A ∩ B ∈ A ∩ B
4 ianor ⊢ ¬ A ∩ B ∈ A ∧ B ∩ A ∈ B ↔ ¬ A ∩ B ∈ A ∨ ¬ B ∩ A ∈ B
5 elin ⊢ A ∩ B ∈ A ∩ B ↔ A ∩ B ∈ A ∧ A ∩ B ∈ B
6 incom ⊢ A ∩ B = B ∩ A
7 6 eleq1i ⊢ A ∩ B ∈ B ↔ B ∩ A ∈ B
8 7 anbi2i ⊢ A ∩ B ∈ A ∧ A ∩ B ∈ B ↔ A ∩ B ∈ A ∧ B ∩ A ∈ B
9 5 8 bitri ⊢ A ∩ B ∈ A ∩ B ↔ A ∩ B ∈ A ∧ B ∩ A ∈ B
10 4 9 xchnxbir ⊢ ¬ A ∩ B ∈ A ∩ B ↔ ¬ A ∩ B ∈ A ∨ ¬ B ∩ A ∈ B
11 3 10 sylib ⊢ Ord ⁡ A ∧ Ord ⁡ B → ¬ A ∩ B ∈ A ∨ ¬ B ∩ A ∈ B
12 inss1 ⊢ A ∩ B ⊆ A
13 ordsseleq ⊢ Ord ⁡ A ∩ B ∧ Ord ⁡ A → A ∩ B ⊆ A ↔ A ∩ B ∈ A ∨ A ∩ B = A
14 12 13 mpbii ⊢ Ord ⁡ A ∩ B ∧ Ord ⁡ A → A ∩ B ∈ A ∨ A ∩ B = A
15 1 14 sylan ⊢ Ord ⁡ A ∧ Ord ⁡ B ∧ Ord ⁡ A → A ∩ B ∈ A ∨ A ∩ B = A
16 15 anabss1 ⊢ Ord ⁡ A ∧ Ord ⁡ B → A ∩ B ∈ A ∨ A ∩ B = A
17 16 ord ⊢ Ord ⁡ A ∧ Ord ⁡ B → ¬ A ∩ B ∈ A → A ∩ B = A
18 dfss2 ⊢ A ⊆ B ↔ A ∩ B = A
19 17 18 imbitrrdi ⊢ Ord ⁡ A ∧ Ord ⁡ B → ¬ A ∩ B ∈ A → A ⊆ B
20 ordin ⊢ Ord ⁡ B ∧ Ord ⁡ A → Ord ⁡ B ∩ A
21 inss1 ⊢ B ∩ A ⊆ B
22 ordsseleq ⊢ Ord ⁡ B ∩ A ∧ Ord ⁡ B → B ∩ A ⊆ B ↔ B ∩ A ∈ B ∨ B ∩ A = B
23 21 22 mpbii ⊢ Ord ⁡ B ∩ A ∧ Ord ⁡ B → B ∩ A ∈ B ∨ B ∩ A = B
24 20 23 sylan ⊢ Ord ⁡ B ∧ Ord ⁡ A ∧ Ord ⁡ B → B ∩ A ∈ B ∨ B ∩ A = B
25 24 anabss4 ⊢ Ord ⁡ A ∧ Ord ⁡ B → B ∩ A ∈ B ∨ B ∩ A = B
26 25 ord ⊢ Ord ⁡ A ∧ Ord ⁡ B → ¬ B ∩ A ∈ B → B ∩ A = B
27 dfss2 ⊢ B ⊆ A ↔ B ∩ A = B
28 26 27 imbitrrdi ⊢ Ord ⁡ A ∧ Ord ⁡ B → ¬ B ∩ A ∈ B → B ⊆ A
29 19 28 orim12d ⊢ Ord ⁡ A ∧ Ord ⁡ B → ¬ A ∩ B ∈ A ∨ ¬ B ∩ A ∈ B → A ⊆ B ∨ B ⊆ A
30 11 29 mpd ⊢ Ord ⁡ A ∧ Ord ⁡ B → A ⊆ B ∨ B ⊆ A
31 sspsstri ⊢ A ⊆ B ∨ B ⊆ A ↔ A ⊂ B ∨ A = B ∨ B ⊂ A
32 30 31 sylib ⊢ Ord ⁡ A ∧ Ord ⁡ B → A ⊂ B ∨ A = B ∨ B ⊂ A
33 ordelpss ⊢ Ord ⁡ A ∧ Ord ⁡ B → A ∈ B ↔ A ⊂ B
34 biidd ⊢ Ord ⁡ A ∧ Ord ⁡ B → A = B ↔ A = B
35 ordelpss ⊢ Ord ⁡ B ∧ Ord ⁡ A → B ∈ A ↔ B ⊂ A
36 35 ancoms ⊢ Ord ⁡ A ∧ Ord ⁡ B → B ∈ A ↔ B ⊂ A
37 33 34 36 3orbi123d ⊢ Ord ⁡ A ∧ Ord ⁡ B → A ∈ B ∨ A = B ∨ B ∈ A ↔ A ⊂ B ∨ A = B ∨ B ⊂ A
38 32 37 mpbird ⊢ Ord ⁡ A ∧ Ord ⁡ B → A ∈ B ∨ A = B ∨ B ∈ A