Metamath Proof Explorer


Theorem prsdm

Description: Domain of the relation of a proset. (Contributed by Thierry Arnoux, 11-Sep-2015)

Ref Expression
Hypotheses ordtNEW.b B = Base K
ordtNEW.l ˙ = K B × B
Assertion prsdm K Proset dom ˙ = B

Proof

Step Hyp Ref Expression
1 ordtNEW.b B = Base K
2 ordtNEW.l ˙ = K B × B
3 2 dmeqi dom ˙ = dom K B × B
4 3 eleq2i x dom ˙ x dom K B × B
5 eqid K = K
6 1 5 prsref K Proset x B x K x
7 df-br x K x x x K
8 6 7 sylib K Proset x B x x K
9 simpr K Proset x B x B
10 9 9 opelxpd K Proset x B x x B × B
11 8 10 elind K Proset x B x x K B × B
12 vex x V
13 opeq2 y = x x y = x x
14 13 eleq1d y = x x y K B × B x x K B × B
15 12 14 spcev x x K B × B y x y K B × B
16 11 15 syl K Proset x B y x y K B × B
17 16 ex K Proset x B y x y K B × B
18 elinel2 x y K B × B x y B × B
19 opelxp1 x y B × B x B
20 18 19 syl x y K B × B x B
21 20 exlimiv y x y K B × B x B
22 17 21 impbid1 K Proset x B y x y K B × B
23 12 eldm2 x dom K B × B y x y K B × B
24 22 23 syl6rbbr K Proset x dom K B × B x B
25 4 24 syl5bb K Proset x dom ˙ x B
26 25 eqrdv K Proset dom ˙ = B