Metamath Proof Explorer


Theorem pwdjudom

Description: A property of dominance over a powerset, and a main lemma for gchac . Similar to Lemma 2.3 of KanamoriPincus p. 420. (Contributed by Mario Carneiro, 15-May-2015)

Ref Expression
Assertion pwdjudom ⊢ 𝒫 A ⊔︀ A ≼ A ⊔︀ B → 𝒫 A ≼ B

Proof

Step Hyp Ref Expression
1 canthwdom ⊢ ¬ 𝒫 A ≼ * A
2 0ex ⊢ ∅ ∈ V
3 reldom ⊢ Rel ⁡ ≼
4 3 brrelex2i ⊢ 𝒫 A ⊔︀ A ≼ A ⊔︀ B → A ⊔︀ B ∈ V
5 djuexb ⊢ A ∈ V ∧ B ∈ V ↔ A ⊔︀ B ∈ V
6 4 5 sylibr ⊢ 𝒫 A ⊔︀ A ≼ A ⊔︀ B → A ∈ V ∧ B ∈ V
7 6 simpld ⊢ 𝒫 A ⊔︀ A ≼ A ⊔︀ B → A ∈ V
8 xpsnen2g ⊢ ∅ ∈ V ∧ A ∈ V → ∅ × A ≈ A
9 2 7 8 sylancr ⊢ 𝒫 A ⊔︀ A ≼ A ⊔︀ B → ∅ × A ≈ A
10 endom ⊢ ∅ × A ≈ A → ∅ × A ≼ A
11 domwdom ⊢ ∅ × A ≼ A → ∅ × A ≼ * A
12 wdomtr ⊢ 𝒫 A ≼ * ∅ × A ∧ ∅ × A ≼ * A → 𝒫 A ≼ * A
13 12 expcom ⊢ ∅ × A ≼ * A → 𝒫 A ≼ * ∅ × A → 𝒫 A ≼ * A
14 9 10 11 13 4syl ⊢ 𝒫 A ⊔︀ A ≼ A ⊔︀ B → 𝒫 A ≼ * ∅ × A → 𝒫 A ≼ * A
15 1 14 mtoi ⊢ 𝒫 A ⊔︀ A ≼ A ⊔︀ B → ¬ 𝒫 A ≼ * ∅ × A
16 pwdjuen ⊢ A ∈ V ∧ A ∈ V → 𝒫 A ⊔︀ A ≈ 𝒫 A × 𝒫 A
17 7 7 16 syl2anc ⊢ 𝒫 A ⊔︀ A ≼ A ⊔︀ B → 𝒫 A ⊔︀ A ≈ 𝒫 A × 𝒫 A
18 domen1 ⊢ 𝒫 A ⊔︀ A ≈ 𝒫 A × 𝒫 A → 𝒫 A ⊔︀ A ≼ A ⊔︀ B ↔ 𝒫 A × 𝒫 A ≼ A ⊔︀ B
19 17 18 syl ⊢ 𝒫 A ⊔︀ A ≼ A ⊔︀ B → 𝒫 A ⊔︀ A ≼ A ⊔︀ B ↔ 𝒫 A × 𝒫 A ≼ A ⊔︀ B
20 19 ibi ⊢ 𝒫 A ⊔︀ A ≼ A ⊔︀ B → 𝒫 A × 𝒫 A ≼ A ⊔︀ B
21 df-dju ⊢ A ⊔︀ B = ∅ × A ∪ 1 𝑜 × B
22 20 21 breqtrdi ⊢ 𝒫 A ⊔︀ A ≼ A ⊔︀ B → 𝒫 A × 𝒫 A ≼ ∅ × A ∪ 1 𝑜 × B
23 unxpwdom ⊢ 𝒫 A × 𝒫 A ≼ ∅ × A ∪ 1 𝑜 × B → 𝒫 A ≼ * ∅ × A ∨ 𝒫 A ≼ 1 𝑜 × B
24 22 23 syl ⊢ 𝒫 A ⊔︀ A ≼ A ⊔︀ B → 𝒫 A ≼ * ∅ × A ∨ 𝒫 A ≼ 1 𝑜 × B
25 24 ord ⊢ 𝒫 A ⊔︀ A ≼ A ⊔︀ B → ¬ 𝒫 A ≼ * ∅ × A → 𝒫 A ≼ 1 𝑜 × B
26 15 25 mpd ⊢ 𝒫 A ⊔︀ A ≼ A ⊔︀ B → 𝒫 A ≼ 1 𝑜 × B
27 1on ⊢ 1 𝑜 ∈ On
28 6 simprd ⊢ 𝒫 A ⊔︀ A ≼ A ⊔︀ B → B ∈ V
29 xpsnen2g ⊢ 1 𝑜 ∈ On ∧ B ∈ V → 1 𝑜 × B ≈ B
30 27 28 29 sylancr ⊢ 𝒫 A ⊔︀ A ≼ A ⊔︀ B → 1 𝑜 × B ≈ B
31 domentr ⊢ 𝒫 A ≼ 1 𝑜 × B ∧ 1 𝑜 × B ≈ B → 𝒫 A ≼ B
32 26 30 31 syl2anc ⊢ 𝒫 A ⊔︀ A ≼ A ⊔︀ B → 𝒫 A ≼ B