Metamath Proof Explorer


Theorem pwsgsum

Description: Finite commutative sums in a power structure are taken componentwise. (Contributed by Stefan O'Rear, 1-Feb-2015) (Revised by Mario Carneiro, 3-Jul-2015) (Revised by AV, 9-Jun-2019)

Ref Expression
Hypotheses pwsgsum.y ⊢ Y = R ↑ 𝑠 I
pwsgsum.b ⊢ B = Base R
pwsgsum.z ⊢ 0 ˙ = 0 Y
pwsgsum.i ⊢ φ → I ∈ V
pwsgsum.j ⊢ φ → J ∈ W
pwsgsum.r ⊢ φ → R ∈ CMnd
pwsgsum.f ⊢ φ ∧ x ∈ I ∧ y ∈ J → U ∈ B
pwsgsum.w ⊢ φ → finSupp 0 ˙⁡ y ∈ J ⟼ x ∈ I ⟼ U
Assertion pwsgsum ⊢ φ → ∑ Y y ∈ J x ∈ I ⟼ U = x ∈ I ⟼ ∑ R y ∈ J U

Proof

Step Hyp Ref Expression
1 pwsgsum.y ⊢ Y = R ↑ 𝑠 I
2 pwsgsum.b ⊢ B = Base R
3 pwsgsum.z ⊢ 0 ˙ = 0 Y
4 pwsgsum.i ⊢ φ → I ∈ V
5 pwsgsum.j ⊢ φ → J ∈ W
6 pwsgsum.r ⊢ φ → R ∈ CMnd
7 pwsgsum.f ⊢ φ ∧ x ∈ I ∧ y ∈ J → U ∈ B
8 pwsgsum.w ⊢ φ → finSupp 0 ˙⁡ y ∈ J ⟼ x ∈ I ⟼ U
9 eqid ⊢ Scalar ⁡ R = Scalar ⁡ R
10 1 9 pwsval ⊢ R ∈ CMnd ∧ I ∈ V → Y = Scalar ⁡ R ⨉ 𝑠 I × R
11 6 4 10 syl2anc ⊢ φ → Y = Scalar ⁡ R ⨉ 𝑠 I × R
12 11 oveq1d ⊢ φ → ∑ Y y ∈ J x ∈ I ⟼ U = ∑ Scalar ⁡ R ⨉ 𝑠 I × R y ∈ J x ∈ I ⟼ U
13 fconstmpt ⊢ I × R = x ∈ I ⟼ R
14 13 oveq2i ⊢ Scalar ⁡ R ⨉ 𝑠 I × R = Scalar ⁡ R ⨉ 𝑠 x ∈ I ⟼ R
15 eqid ⊢ 0 Scalar ⁡ R ⨉ 𝑠 I × R = 0 Scalar ⁡ R ⨉ 𝑠 I × R
16 fvexd ⊢ φ → Scalar ⁡ R ∈ V
17 6 adantr ⊢ φ ∧ x ∈ I → R ∈ CMnd
18 11 fveq2d ⊢ φ → 0 Y = 0 Scalar ⁡ R ⨉ 𝑠 I × R
19 3 18 eqtrid ⊢ φ → 0 ˙ = 0 Scalar ⁡ R ⨉ 𝑠 I × R
20 8 19 breqtrd ⊢ φ → finSupp 0 Scalar ⁡ R ⨉ 𝑠 I × R ⁡ y ∈ J ⟼ x ∈ I ⟼ U
21 14 2 15 4 5 16 17 7 20 prdsgsum ⊢ φ → ∑ Scalar ⁡ R ⨉ 𝑠 I × R y ∈ J x ∈ I ⟼ U = x ∈ I ⟼ ∑ R y ∈ J U
22 12 21 eqtrd ⊢ φ → ∑ Y y ∈ J x ∈ I ⟼ U = x ∈ I ⟼ ∑ R y ∈ J U