Metamath Proof Explorer


Theorem ragperp

Description: Deduce that two lines are perpendicular from a right angle statement. One direction of theorem 8.13 of Schwabhauser p. 59. (Contributed by Thierry Arnoux, 20-Oct-2019)

Ref Expression
Hypotheses isperp.p ⊢ P = Base G
isperp.d ⊢ - ˙ = dist ⁡ G
isperp.i ⊢ I = Itv ⁡ G
isperp.l ⊢ L = Line 𝒢 ⁡ G
isperp.g ⊢ φ → G ∈ 𝒢 Tarski
isperp.a ⊢ φ → A ∈ ran ⁡ L
ragperp.b ⊢ φ → B ∈ ran ⁡ L
ragperp.x ⊢ φ → X ∈ A ∩ B
ragperp.u ⊢ φ → U ∈ A
ragperp.v ⊢ φ → V ∈ B
ragperp.1 ⊢ φ → U ≠ X
ragperp.2 ⊢ φ → V ≠ X
ragperp.r ⊢ φ → ⟨“ UXV ”⟩ ∈ ∟ 𝒢 ⁡ G
Assertion ragperp ⊢ φ → A ⟂ 𝒢 ⁡ G B

Proof

Step Hyp Ref Expression
1 isperp.p ⊢ P = Base G
2 isperp.d ⊢ - ˙ = dist ⁡ G
3 isperp.i ⊢ I = Itv ⁡ G
4 isperp.l ⊢ L = Line 𝒢 ⁡ G
5 isperp.g ⊢ φ → G ∈ 𝒢 Tarski
6 isperp.a ⊢ φ → A ∈ ran ⁡ L
7 ragperp.b ⊢ φ → B ∈ ran ⁡ L
8 ragperp.x ⊢ φ → X ∈ A ∩ B
9 ragperp.u ⊢ φ → U ∈ A
10 ragperp.v ⊢ φ → V ∈ B
11 ragperp.1 ⊢ φ → U ≠ X
12 ragperp.2 ⊢ φ → V ≠ X
13 ragperp.r ⊢ φ → ⟨“ UXV ”⟩ ∈ ∟ 𝒢 ⁡ G
14 eqid ⊢ pInv 𝒢 ⁡ G = pInv 𝒢 ⁡ G
15 5 adantr ⊢ φ ∧ u ∈ A ∧ v ∈ B → G ∈ 𝒢 Tarski
16 7 adantr ⊢ φ ∧ u ∈ A ∧ v ∈ B → B ∈ ran ⁡ L
17 simprr ⊢ φ ∧ u ∈ A ∧ v ∈ B → v ∈ B
18 1 4 3 15 16 17 tglnpt ⊢ φ ∧ u ∈ A ∧ v ∈ B → v ∈ P
19 6 adantr ⊢ φ ∧ u ∈ A ∧ v ∈ B → A ∈ ran ⁡ L
20 8 elin1d ⊢ φ → X ∈ A
21 20 adantr ⊢ φ ∧ u ∈ A ∧ v ∈ B → X ∈ A
22 1 4 3 15 19 21 tglnpt ⊢ φ ∧ u ∈ A ∧ v ∈ B → X ∈ P
23 simprl ⊢ φ ∧ u ∈ A ∧ v ∈ B → u ∈ A
24 1 4 3 15 19 23 tglnpt ⊢ φ ∧ u ∈ A ∧ v ∈ B → u ∈ P
25 10 adantr ⊢ φ ∧ u ∈ A ∧ v ∈ B → V ∈ B
26 1 4 3 15 16 25 tglnpt ⊢ φ ∧ u ∈ A ∧ v ∈ B → V ∈ P
27 9 adantr ⊢ φ ∧ u ∈ A ∧ v ∈ B → U ∈ A
28 1 4 3 15 19 27 tglnpt ⊢ φ ∧ u ∈ A ∧ v ∈ B → U ∈ P
29 13 adantr ⊢ φ ∧ u ∈ A ∧ v ∈ B → ⟨“ UXV ”⟩ ∈ ∟ 𝒢 ⁡ G
30 11 adantr ⊢ φ ∧ u ∈ A ∧ v ∈ B → U ≠ X
31 9 ad2antrr ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = u → U ∈ A
32 5 ad2antrr ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = u → G ∈ 𝒢 Tarski
33 22 adantr ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = u → X ∈ P
34 24 adantr ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = u → u ∈ P
35 simpr ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = u → ¬ X = u
36 35 neqned ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = u → X ≠ u
37 6 ad2antrr ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = u → A ∈ ran ⁡ L
38 20 ad2antrr ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = u → X ∈ A
39 23 adantr ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = u → u ∈ A
40 1 3 4 32 33 34 36 36 37 38 39 tglinethru ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = u → A = X L u
41 31 40 eleqtrd ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = u → U ∈ X L u
42 41 ex ⊢ φ ∧ u ∈ A ∧ v ∈ B → ¬ X = u → U ∈ X L u
43 42 orrd ⊢ φ ∧ u ∈ A ∧ v ∈ B → X = u ∨ U ∈ X L u
44 43 orcomd ⊢ φ ∧ u ∈ A ∧ v ∈ B → U ∈ X L u ∨ X = u
45 1 2 3 4 14 15 28 22 26 24 29 30 44 ragcol ⊢ φ ∧ u ∈ A ∧ v ∈ B → ⟨“ uXV ”⟩ ∈ ∟ 𝒢 ⁡ G
46 1 2 3 4 14 15 24 22 26 45 ragcom ⊢ φ ∧ u ∈ A ∧ v ∈ B → ⟨“ VXu ”⟩ ∈ ∟ 𝒢 ⁡ G
47 12 adantr ⊢ φ ∧ u ∈ A ∧ v ∈ B → V ≠ X
48 10 ad2antrr ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = v → V ∈ B
49 5 ad2antrr ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = v → G ∈ 𝒢 Tarski
50 22 adantr ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = v → X ∈ P
51 18 adantr ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = v → v ∈ P
52 simpr ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = v → ¬ X = v
53 52 neqned ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = v → X ≠ v
54 7 ad2antrr ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = v → B ∈ ran ⁡ L
55 8 elin2d ⊢ φ → X ∈ B
56 55 ad2antrr ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = v → X ∈ B
57 17 adantr ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = v → v ∈ B
58 1 3 4 49 50 51 53 53 54 56 57 tglinethru ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = v → B = X L v
59 48 58 eleqtrd ⊢ φ ∧ u ∈ A ∧ v ∈ B ∧ ¬ X = v → V ∈ X L v
60 59 ex ⊢ φ ∧ u ∈ A ∧ v ∈ B → ¬ X = v → V ∈ X L v
61 60 orrd ⊢ φ ∧ u ∈ A ∧ v ∈ B → X = v ∨ V ∈ X L v
62 61 orcomd ⊢ φ ∧ u ∈ A ∧ v ∈ B → V ∈ X L v ∨ X = v
63 1 2 3 4 14 15 26 22 24 18 46 47 62 ragcol ⊢ φ ∧ u ∈ A ∧ v ∈ B → ⟨“ vXu ”⟩ ∈ ∟ 𝒢 ⁡ G
64 1 2 3 4 14 15 18 22 24 63 ragcom ⊢ φ ∧ u ∈ A ∧ v ∈ B → ⟨“ uXv ”⟩ ∈ ∟ 𝒢 ⁡ G
65 64 ralrimivva ⊢ φ → ∀ u ∈ A ∀ v ∈ B ⟨“ uXv ”⟩ ∈ ∟ 𝒢 ⁡ G
66 1 2 3 4 5 6 7 8 isperp2 ⊢ φ → A ⟂ 𝒢 ⁡ G B ↔ ∀ u ∈ A ∀ v ∈ B ⟨“ uXv ”⟩ ∈ ∟ 𝒢 ⁡ G
67 65 66 mpbird ⊢ φ → A ⟂ 𝒢 ⁡ G B