Metamath Proof Explorer


Theorem rexanuz3

Description: Combine two different upper integer properties into one, for a single integer. (Contributed by Glauco Siliprandi, 26-Jun-2021)

Ref Expression
Hypotheses rexanuz3.1 ⊢ Ⅎ j φ
rexanuz3.2 ⊢ Z = ℤ ≥ M
rexanuz3.3 ⊢ φ → ∃ j ∈ Z ∀ k ∈ ℤ ≥ j χ
rexanuz3.4 ⊢ φ → ∃ j ∈ Z ∀ k ∈ ℤ ≥ j ψ
rexanuz3.5 ⊢ k = j → χ ↔ θ
rexanuz3.6 ⊢ k = j → ψ ↔ τ
Assertion rexanuz3 ⊢ φ → ∃ j ∈ Z θ ∧ τ

Proof

Step Hyp Ref Expression
1 rexanuz3.1 ⊢ Ⅎ j φ
2 rexanuz3.2 ⊢ Z = ℤ ≥ M
3 rexanuz3.3 ⊢ φ → ∃ j ∈ Z ∀ k ∈ ℤ ≥ j χ
4 rexanuz3.4 ⊢ φ → ∃ j ∈ Z ∀ k ∈ ℤ ≥ j ψ
5 rexanuz3.5 ⊢ k = j → χ ↔ θ
6 rexanuz3.6 ⊢ k = j → ψ ↔ τ
7 3 4 jca ⊢ φ → ∃ j ∈ Z ∀ k ∈ ℤ ≥ j χ ∧ ∃ j ∈ Z ∀ k ∈ ℤ ≥ j ψ
8 2 rexanuz2 ⊢ ∃ j ∈ Z ∀ k ∈ ℤ ≥ j χ ∧ ψ ↔ ∃ j ∈ Z ∀ k ∈ ℤ ≥ j χ ∧ ∃ j ∈ Z ∀ k ∈ ℤ ≥ j ψ
9 7 8 sylibr ⊢ φ → ∃ j ∈ Z ∀ k ∈ ℤ ≥ j χ ∧ ψ
10 2 eleq2i ⊢ j ∈ Z ↔ j ∈ ℤ ≥ M
11 10 biimpi ⊢ j ∈ Z → j ∈ ℤ ≥ M
12 eluzelz ⊢ j ∈ ℤ ≥ M → j ∈ ℤ
13 uzid ⊢ j ∈ ℤ → j ∈ ℤ ≥ j
14 11 12 13 3syl ⊢ j ∈ Z → j ∈ ℤ ≥ j
15 14 adantr ⊢ j ∈ Z ∧ ∀ k ∈ ℤ ≥ j χ ∧ ψ → j ∈ ℤ ≥ j
16 simpr ⊢ j ∈ Z ∧ ∀ k ∈ ℤ ≥ j χ ∧ ψ → ∀ k ∈ ℤ ≥ j χ ∧ ψ
17 5 6 anbi12d ⊢ k = j → χ ∧ ψ ↔ θ ∧ τ
18 17 rspcva ⊢ j ∈ ℤ ≥ j ∧ ∀ k ∈ ℤ ≥ j χ ∧ ψ → θ ∧ τ
19 15 16 18 syl2anc ⊢ j ∈ Z ∧ ∀ k ∈ ℤ ≥ j χ ∧ ψ → θ ∧ τ
20 19 adantll ⊢ φ ∧ j ∈ Z ∧ ∀ k ∈ ℤ ≥ j χ ∧ ψ → θ ∧ τ
21 20 ex ⊢ φ ∧ j ∈ Z → ∀ k ∈ ℤ ≥ j χ ∧ ψ → θ ∧ τ
22 21 ex ⊢ φ → j ∈ Z → ∀ k ∈ ℤ ≥ j χ ∧ ψ → θ ∧ τ
23 1 22 reximdai ⊢ φ → ∃ j ∈ Z ∀ k ∈ ℤ ≥ j χ ∧ ψ → ∃ j ∈ Z θ ∧ τ
24 9 23 mpd ⊢ φ → ∃ j ∈ Z θ ∧ τ