Metamath Proof Explorer


Theorem ruclem13

Description: Lemma for ruc . There is no function that maps NN onto RR . (Use nex if you want this in the form -. E. f f : NN -onto-> RR .) (Contributed by NM, 14-Oct-2004) (Proof shortened by Fan Zheng, 6-Jun-2016)

Ref Expression
Assertion ruclem13 ⊢ ¬ F : ℕ ⟶ onto ℝ

Proof

Step Hyp Ref Expression
1 forn ⊢ F : ℕ ⟶ onto ℝ → ran ⁡ F = ℝ
2 1 difeq2d ⊢ F : ℕ ⟶ onto ℝ → ℝ ∖ ran ⁡ F = ℝ ∖ ℝ
3 difid ⊢ ℝ ∖ ℝ = ∅
4 2 3 eqtrdi ⊢ F : ℕ ⟶ onto ℝ → ℝ ∖ ran ⁡ F = ∅
5 reex ⊢ ℝ ∈ V
6 5 5 xpex ⊢ ℝ 2 ∈ V
7 6 5 mpoex ⊢ x ∈ ℝ 2 , y ∈ ℝ ⟼ ⦋ 1 st ⁡ x + 2 nd ⁡ x 2 / m⦌ if m < y 1 st ⁡ x m m + 2 nd ⁡ x 2 2 nd ⁡ x ∈ V
8 7 isseti ⊢ ∃ d d = x ∈ ℝ 2 , y ∈ ℝ ⟼ ⦋ 1 st ⁡ x + 2 nd ⁡ x 2 / m⦌ if m < y 1 st ⁡ x m m + 2 nd ⁡ x 2 2 nd ⁡ x
9 fof ⊢ F : ℕ ⟶ onto ℝ → F : ℕ ⟶ ℝ
10 9 adantr ⊢ F : ℕ ⟶ onto ℝ ∧ d = x ∈ ℝ 2 , y ∈ ℝ ⟼ ⦋ 1 st ⁡ x + 2 nd ⁡ x 2 / m⦌ if m < y 1 st ⁡ x m m + 2 nd ⁡ x 2 2 nd ⁡ x → F : ℕ ⟶ ℝ
11 simpr ⊢ F : ℕ ⟶ onto ℝ ∧ d = x ∈ ℝ 2 , y ∈ ℝ ⟼ ⦋ 1 st ⁡ x + 2 nd ⁡ x 2 / m⦌ if m < y 1 st ⁡ x m m + 2 nd ⁡ x 2 2 nd ⁡ x → d = x ∈ ℝ 2 , y ∈ ℝ ⟼ ⦋ 1 st ⁡ x + 2 nd ⁡ x 2 / m⦌ if m < y 1 st ⁡ x m m + 2 nd ⁡ x 2 2 nd ⁡ x
12 eqid ⊢ 0 0 1 ∪ F = 0 0 1 ∪ F
13 eqid ⊢ seq 0 d 0 0 1 ∪ F = seq 0 d 0 0 1 ∪ F
14 eqid ⊢ sup ran ⁡ 1 st ∘ seq 0 d 0 0 1 ∪ F ℝ < = sup ran ⁡ 1 st ∘ seq 0 d 0 0 1 ∪ F ℝ <
15 10 11 12 13 14 ruclem12 ⊢ F : ℕ ⟶ onto ℝ ∧ d = x ∈ ℝ 2 , y ∈ ℝ ⟼ ⦋ 1 st ⁡ x + 2 nd ⁡ x 2 / m⦌ if m < y 1 st ⁡ x m m + 2 nd ⁡ x 2 2 nd ⁡ x → sup ran ⁡ 1 st ∘ seq 0 d 0 0 1 ∪ F ℝ < ∈ ℝ ∖ ran ⁡ F
16 n0i ⊢ sup ran ⁡ 1 st ∘ seq 0 d 0 0 1 ∪ F ℝ < ∈ ℝ ∖ ran ⁡ F → ¬ ℝ ∖ ran ⁡ F = ∅
17 15 16 syl ⊢ F : ℕ ⟶ onto ℝ ∧ d = x ∈ ℝ 2 , y ∈ ℝ ⟼ ⦋ 1 st ⁡ x + 2 nd ⁡ x 2 / m⦌ if m < y 1 st ⁡ x m m + 2 nd ⁡ x 2 2 nd ⁡ x → ¬ ℝ ∖ ran ⁡ F = ∅
18 17 ex ⊢ F : ℕ ⟶ onto ℝ → d = x ∈ ℝ 2 , y ∈ ℝ ⟼ ⦋ 1 st ⁡ x + 2 nd ⁡ x 2 / m⦌ if m < y 1 st ⁡ x m m + 2 nd ⁡ x 2 2 nd ⁡ x → ¬ ℝ ∖ ran ⁡ F = ∅
19 18 exlimdv ⊢ F : ℕ ⟶ onto ℝ → ∃ d d = x ∈ ℝ 2 , y ∈ ℝ ⟼ ⦋ 1 st ⁡ x + 2 nd ⁡ x 2 / m⦌ if m < y 1 st ⁡ x m m + 2 nd ⁡ x 2 2 nd ⁡ x → ¬ ℝ ∖ ran ⁡ F = ∅
20 8 19 mpi ⊢ F : ℕ ⟶ onto ℝ → ¬ ℝ ∖ ran ⁡ F = ∅
21 4 20 pm2.65i ⊢ ¬ F : ℕ ⟶ onto ℝ