Metamath Proof Explorer


Theorem shftvalg

Description: Value of a sequence shifted by A . (Contributed by Scott Fenton, 16-Dec-2017)

Ref Expression
Assertion shftvalg ⊢ F ∈ V ∧ A ∈ ℂ ∧ B ∈ ℂ → F shift A ⁡ B = F ⁡ B − A

Proof

Step Hyp Ref Expression
1 oveq1 ⊢ f = F → f shift A = F shift A
2 1 fveq1d ⊢ f = F → f shift A ⁡ B = F shift A ⁡ B
3 fveq1 ⊢ f = F → f ⁡ B − A = F ⁡ B − A
4 2 3 eqeq12d ⊢ f = F → f shift A ⁡ B = f ⁡ B − A ↔ F shift A ⁡ B = F ⁡ B − A
5 4 imbi2d ⊢ f = F → A ∈ ℂ ∧ B ∈ ℂ → f shift A ⁡ B = f ⁡ B − A ↔ A ∈ ℂ ∧ B ∈ ℂ → F shift A ⁡ B = F ⁡ B − A
6 vex ⊢ f ∈ V
7 6 shftval ⊢ A ∈ ℂ ∧ B ∈ ℂ → f shift A ⁡ B = f ⁡ B − A
8 5 7 vtoclg ⊢ F ∈ V → A ∈ ℂ ∧ B ∈ ℂ → F shift A ⁡ B = F ⁡ B − A
9 8 3impib ⊢ F ∈ V ∧ A ∈ ℂ ∧ B ∈ ℂ → F shift A ⁡ B = F ⁡ B − A