Metamath Proof Explorer


Theorem srng1

Description: The conjugate of the ring identity is the identity. (This is sometimes taken as an axiom, and indeed the proof here follows because we defined *r to be a ring homomorphism, which preserves 1; nevertheless, it is redundant, as can be seen from the proof of issrngd .) (Contributed by Mario Carneiro, 6-Oct-2015)

Ref Expression
Hypotheses srng1.i ⊢ ∗ ˙ = * R
srng1.t ⊢ 1 ˙ = 1 R
Assertion srng1 ⊢ R ∈ *-Ring → ∗ ˙ ⁡ 1 ˙ = 1 ˙

Proof

Step Hyp Ref Expression
1 srng1.i ⊢ ∗ ˙ = * R
2 srng1.t ⊢ 1 ˙ = 1 R
3 srngring ⊢ R ∈ *-Ring → R ∈ Ring
4 eqid ⊢ Base R = Base R
5 4 2 ringidcl ⊢ R ∈ Ring → 1 ˙ ∈ Base R
6 eqid ⊢ ∗ 𝑟𝑓 ⁡ R = ∗ 𝑟𝑓 ⁡ R
7 4 1 6 stafval ⊢ 1 ˙ ∈ Base R → ∗ 𝑟𝑓 ⁡ R ⁡ 1 ˙ = ∗ ˙ ⁡ 1 ˙
8 3 5 7 3syl ⊢ R ∈ *-Ring → ∗ 𝑟𝑓 ⁡ R ⁡ 1 ˙ = ∗ ˙ ⁡ 1 ˙
9 eqid ⊢ opp r ⁡ R = opp r ⁡ R
10 9 6 srngrhm ⊢ R ∈ *-Ring → ∗ 𝑟𝑓 ⁡ R ∈ R RingHom opp r ⁡ R
11 9 2 oppr1 ⊢ 1 ˙ = 1 opp r ⁡ R
12 2 11 rhm1 ⊢ ∗ 𝑟𝑓 ⁡ R ∈ R RingHom opp r ⁡ R → ∗ 𝑟𝑓 ⁡ R ⁡ 1 ˙ = 1 ˙
13 10 12 syl ⊢ R ∈ *-Ring → ∗ 𝑟𝑓 ⁡ R ⁡ 1 ˙ = 1 ˙
14 8 13 eqtr3d ⊢ R ∈ *-Ring → ∗ ˙ ⁡ 1 ˙ = 1 ˙