Metamath Proof Explorer


Theorem submnd0OLD

Description: Obsolete version of submnd0 as of 12-Aug-2026. The zero of a submonoid is the same as the zero in the parent monoid. (Contributed by Mario Carneiro, 10-Jan-2015) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypotheses submnd0.b B = Base G
submnd0.z 0 ˙ = 0 G
submnd0.h H = G 𝑠 S
Assertion submnd0OLD G Mnd H Mnd S B 0 ˙ S 0 ˙ = 0 H

Proof

Step Hyp Ref Expression
1 submnd0.b B = Base G
2 submnd0.z 0 ˙ = 0 G
3 submnd0.h H = G 𝑠 S
4 eqid Base H = Base H
5 eqid 0 H = 0 H
6 eqid + H = + H
7 simprr G Mnd H Mnd S B 0 ˙ S 0 ˙ S
8 3 1 ressbas2 S B S = Base H
9 8 ad2antrl G Mnd H Mnd S B 0 ˙ S S = Base H
10 7 9 eleqtrd G Mnd H Mnd S B 0 ˙ S 0 ˙ Base H
11 fvex Base H V
12 9 11 eqeltrdi G Mnd H Mnd S B 0 ˙ S S V
13 12 adantr G Mnd H Mnd S B 0 ˙ S x Base H S V
14 eqid + G = + G
15 3 14 ressplusg S V + G = + H
16 13 15 syl G Mnd H Mnd S B 0 ˙ S x Base H + G = + H
17 16 oveqd G Mnd H Mnd S B 0 ˙ S x Base H 0 ˙ + G x = 0 ˙ + H x
18 simpll G Mnd H Mnd S B 0 ˙ S G Mnd
19 3 1 ressbasss Base H B
20 19 sseli x Base H x B
21 1 14 2 mndlid G Mnd x B 0 ˙ + G x = x
22 18 20 21 syl2an G Mnd H Mnd S B 0 ˙ S x Base H 0 ˙ + G x = x
23 17 22 eqtr3d G Mnd H Mnd S B 0 ˙ S x Base H 0 ˙ + H x = x
24 16 oveqd G Mnd H Mnd S B 0 ˙ S x Base H x + G 0 ˙ = x + H 0 ˙
25 1 14 2 mndrid G Mnd x B x + G 0 ˙ = x
26 18 20 25 syl2an G Mnd H Mnd S B 0 ˙ S x Base H x + G 0 ˙ = x
27 24 26 eqtr3d G Mnd H Mnd S B 0 ˙ S x Base H x + H 0 ˙ = x
28 4 5 6 10 23 27 ismgmid2 G Mnd H Mnd S B 0 ˙ S 0 ˙ = 0 H