Metamath Proof Explorer


Theorem sucomisnotcard

Description: _om +o 1o is not a cardinal number. (Contributed by RP, 1-Oct-2023)

Ref Expression
Assertion sucomisnotcard ⊢ ¬ ω + 𝑜 1 𝑜 ∈ ran ⁡ card

Proof

Step Hyp Ref Expression
1 omelon ⊢ ω ∈ On
2 sucidg ⊢ ω ∈ On → ω ∈ suc ⁡ ω
3 1 2 ax-mp ⊢ ω ∈ suc ⁡ ω
4 omensuc ⊢ ω ≈ suc ⁡ ω
5 breq1 ⊢ x = ω → x ≈ suc ⁡ ω ↔ ω ≈ suc ⁡ ω
6 5 rspcev ⊢ ω ∈ suc ⁡ ω ∧ ω ≈ suc ⁡ ω → ∃ x ∈ suc ⁡ ω x ≈ suc ⁡ ω
7 3 4 6 mp2an ⊢ ∃ x ∈ suc ⁡ ω x ≈ suc ⁡ ω
8 dfrex2 ⊢ ∃ x ∈ suc ⁡ ω x ≈ suc ⁡ ω ↔ ¬ ∀ x ∈ suc ⁡ ω ¬ x ≈ suc ⁡ ω
9 7 8 mpbi ⊢ ¬ ∀ x ∈ suc ⁡ ω ¬ x ≈ suc ⁡ ω
10 9 intnan ⊢ ¬ suc ⁡ ω ∈ On ∧ ∀ x ∈ suc ⁡ ω ¬ x ≈ suc ⁡ ω
11 oa1suc ⊢ ω ∈ On → ω + 𝑜 1 𝑜 = suc ⁡ ω
12 1 11 ax-mp ⊢ ω + 𝑜 1 𝑜 = suc ⁡ ω
13 12 eleq1i ⊢ ω + 𝑜 1 𝑜 ∈ ran ⁡ card ↔ suc ⁡ ω ∈ ran ⁡ card
14 elrncard ⊢ suc ⁡ ω ∈ ran ⁡ card ↔ suc ⁡ ω ∈ On ∧ ∀ x ∈ suc ⁡ ω ¬ x ≈ suc ⁡ ω
15 13 14 sylbb ⊢ ω + 𝑜 1 𝑜 ∈ ran ⁡ card → suc ⁡ ω ∈ On ∧ ∀ x ∈ suc ⁡ ω ¬ x ≈ suc ⁡ ω
16 10 15 mto ⊢ ¬ ω + 𝑜 1 𝑜 ∈ ran ⁡ card